Question

Sample Response: You would graph the equation f(x) = –x + 3 for input values less than 2. There would be an open circle at the point (2, 1) since the domain for the first piece does not include 2. You would then graph a horizontal line at f(x) = 3 for input values between 2 and 4. There would be a closed circle at (2, 3) and an open circle at (4, 3). Last, you would graph f(x) = 4 – 2x for input values greater than or equal to 4. There would be a closed circle at the point (4, –4) since 4 is in the domain of the third piece.
What did you include in your response? Check all that apply.

There would be an open circle at (2, 1).
There would be a closed circle at (2, 3).
There would be an open circle at (4, 3).
There would be a closed circle at (4, −4).
Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle.

Answer 1

Answer:

Step-by-step explanation:

What did you include in your response? Check all that apply.

There would be an open circle at (2, 1).  Yes

There would be a closed circle at (2, 3).  Yes

There would be an open circle at (4, 3).  Yes

There would be a closed circle at (4, −4).  Yes

Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle.  Yes