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jasenka [17]
3 years ago
14

The list below shows all the possible outcomes for tossing a coin and rolling 1 to 6 number cube. What is the probability that m

ax tosses heads and rolls a number greater than two
Mathematics
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

1/3

Step-by-step explanation:

In the coin there is heads or tails (2 possible results), so the probability of tossing heads is 1/2

For the number cube, we have 6 possible results. If we want a result greater than two, we have 3, 4, 5 or 6, so we have 4 of the 6 results, then the probability is 4/6.

Now, to find the final probability, we multiply both probabilities above:

Probability = (1/2) * (4/6) = 2/6 = 1/3

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Solving equations 15(x)=4(2x+3)
8_murik_8 [283]
The answer is x = 12/7

because you multiply 15 by x to get 15x
15x = 4(2x+3)
next you simplify the right side by using the distributive property by doing 15x = 4(2x) + 4(3)
Then you multiply 2 by 4 to get 8
15x = 8x + 4(3)
and multiply 4 by 3 to get 12
15x = 8x + 12
Now you move terms containing (x) to the left side of the equation.
Since 8x contains the variable to solve for, move it to the left side of the equation by subtracting 8x from both sides.
15x - 8x = 12
subtract 8x from 15x to get 7x
7x = 12
Also , divide each term by 7 and simplify
Divide each term in 7x = 12 by 7
7x/7 = 12/7
Lastly ,  reduce the expression by cancelling  the common factors by
crossing out  all 7s 7x/7 and leave 12/7 as it is, and divide x by 1 to get x by
x = 12/7
So the answer is  x = 12/7 





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