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jasenka [17]
3 years ago
14

The list below shows all the possible outcomes for tossing a coin and rolling 1 to 6 number cube. What is the probability that m

ax tosses heads and rolls a number greater than two
Mathematics
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

1/3

Step-by-step explanation:

In the coin there is heads or tails (2 possible results), so the probability of tossing heads is 1/2

For the number cube, we have 6 possible results. If we want a result greater than two, we have 3, 4, 5 or 6, so we have 4 of the 6 results, then the probability is 4/6.

Now, to find the final probability, we multiply both probabilities above:

Probability = (1/2) * (4/6) = 2/6 = 1/3

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The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?
Elza [17]
You are supposed to use the third option: 3n2 + 6n + 5 = 116.
Take a look at the attachment to see how I got that solution. 
Hope it helps! :)

5 0
3 years ago
Can someone please help me answer this?
ozzi
For this problem i got

7 0
3 years ago
PLZ HELP Simplify the rational expression. State any excluded values. 2x/-5x+x^2
Bas_tet [7]
(2x/-5x)+x^2
(x(2)/(x(-5))+x^2

(-2/5)+x^2, the x values cancel in numerator and denominator and simplify to -2/5
6 0
3 years ago
Read 2 more answers
The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan
Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

\mu = E(X) = np = 100*0.23 = 23

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 23}{4.1}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0
3 years ago
PLEASE HELP !! ILL GIVE BRAINLIEST !!
AveGali [126]

Answer:

Angles and XWY and STR

Step-by-step explanation:

These two angels are alternate exterior angels because:

- They are on different sides of the transversal (the line intersecting the two parallel lines)

- They have the same angle measure

- They are exterior, meaning they are on the outside, not inside (interior)

Hope this helps!!! :)

8 0
3 years ago
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