The answer is b it will always be equal
Answer:
the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Explanation:
Since
Br₂(g) + Cl₂(g) ⇌ 2BrCl(g) , Kp=1.112 at 150 K
denoting BC as BrCl , B as Br₂ , C as Cl₂, p as partial pressure , then
Kp = pBC²/[pB*pC]
solving for pBC
pBC = √(Kp*pB*pC)
replacing values
pBC = √(Kp*pB*pC) = √(1.112*751 torr*737 torr) = 784.52 torr
pBC = 784.52 torr
then the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Answer:
b. - 184 J/K
Explanation:
- ΔSsurr = - ΔH/T....at constant P and T.
∴ ΔHrxn = 54.2 KJ = 54200 J
∴ T = 25°C ≅ 298.15 K
⇒ ΔSsurr = - (54200 J)/(298 K)
⇒ ΔSsurr = - 182 J/K ≅ - 184 J/K
D is the answer sorry if wrong