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madam [21]
3 years ago
9

Ice cubes are placed on a table in a warm room. What happens to the ice particles?

Chemistry
1 answer:
Zinaida [17]3 years ago
7 0

B

Explanation:

I rember when I learned this in 3rd grade

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Will give free brainlist !! :)
luda_lava [24]

Answer:

C is the correct answer

Explanation:

7 0
2 years ago
Read 2 more answers
Name the element described in each of the following:
borishaifa [10]

Alkaline earth metal whose cation isoelectric with Kr is strontium (Sr).

What is Alkaline earth metal?

Six chemical elements from group 2 of the periodic chart make up the alkaline earth metals. They are boron (R), barium (Ba), calcium (Ca), strontium (Sr), magnesium (Mg), beryllium (Be), and radium (Ra). The elements share many characteristics, including being glossy, silvery-white, moderately reactive metals at standard pressure and temperature.

They share a full outer s-orbital structurally, meaning that this orbital includes all two of its electrons, which the alkaline earth metals rapidly lose to form cations with a charge of +2 and an oxidation state of +2.

All of the identified alkaline earth metals are found in nature, albeit radium is not a primordial element but only appears as part of the decay chain of uranium and thorium.

The chemical element strontium has the atomic number 38 and the symbol Sr. Strontium is a soft, silver-white, yellowish metallic element that is an alkaline earth metal and has a strong reactivity to chemicals. When the metal is exposed to air, a thick layer of dark oxide forms. Similar to its two vertical neighbors in the periodic table, barium and calcium, strontium exhibits physical and chemical characteristics. It is mostly obtained from the minerals celestine and strontianite, where it is found naturally.

To learn more about Strontium  click on the link below:

brainly.com/question/19904990

#SPJ4

8 0
2 years ago
Iodine-131 decays with a half-life of 8.02
dlinn [17]
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
3 0
3 years ago
The generic metal a forms an insoluble salt ab(s) and a complex ac5(aq). the equilibrium concentrations in a solution of ac5 wer
Leno4ka [110]

Assuming that the reaction from A and C to AC5 is only one-step (or an elementary reaction) with a balanced chemical reaction of:

<span>A + 5 C  --->  AC5 </span>

Therefore the formation constant can be easily calculated using the following formula for formation constant:

Kf = product of products concentrations / product of reactants concentration

<span>Kf = [AC5] / [A] [C]^5                     </span>

---> Any coefficient from the balanced chemical reaction becomes a power in the formula

Substituting the given values into the equation:

Kf = 0.100 M / (0.100 M) (0.0110 M)^5

Kf = 6,209,213,231

or in simpler terms

<span>Kf = 6.21 * 10^9                  (ANSWER)</span>

3 0
3 years ago
If a:b =2:3and b:c=6:10,find a:c.​
Anni [7]

Explanation:

2 is to 5 is your answer

2:5

4 0
3 years ago
Read 2 more answers
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