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tino4ka555 [31]
3 years ago
13

Write the rate expression for the following reaction. H2+1/2 O2 arrow H2O​

Chemistry
1 answer:
julsineya [31]3 years ago
8 0

Answer:

r=-k[H_2][O_2]^{1/2}

Explanation:

Hello!

In this case, according to the chemical reaction:

H2 + 1/2  O2 --> H2O​

Since both hydrogen and oxygen are the reactants and the rate laws are written in terms of the concentration of reactants and the rate constant, we obtain:

r=-k[H_2][O_2]^{1/2}

Whereas the negative sign represents the consumption of those reactants and the power 1/2 the stoichiometric coefficient of oxygen in the reaction.

Best regards!

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Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L
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Answer:

All of the above.

Explanation:

In positive deviation from Raoult's  Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure  of component A is P_A and vapour pressure of component B is P_B.

P^0_A= Vapour pressure of component A in pure form

P^0_B= Vapour pressure of component B in pure form

x_A=Mole fraction of component A

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The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

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Therefore, P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B

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Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: PCl5(g) → PCl3(g) + Cl2(g)
nalin [4]

Answer:

The value of \Delta H for the desired reaction will be 249.75 KJ.

Explanation:

The desired reaction is shown below

\textrm{PCl}_{5}\left ( g \right )\rightarrow \textrm{PCl}_{3}\left ( g \right )+\textrm{Cl}_{2}\left ( g \right )

The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.

P_{4}\left ( s \right )+6Cl_{2}\left ( g \right )\rightarrow 4PCl_{3}\left ( g \right ) \\4PCl_{5}\left ( g \right )\rightarrow P_{4}\left ( s \right )+10Cl_{2}\left ( g \right )

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\Delta H = 249.75 \textrm{ KJ}

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