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3 years ago

a piece of cheese weighting 2/3 pound is to be divided into 8 equal portions. what will be the weight of each portion?

Mathematics

2 answers:

cricket20 [7]3 years ago

7 0

Answer:

1/12 lb

Step-by-step explanation:

2/3 x 1/8 = 2/24 = 1/12

Naddik [55]3 years ago

3 0

<h2><u>Answer: 1/12</u></h2>

Step-by-step explanation: 2/3 / 8/1 is actually multiplying the first number by the reciprocal of the second. So 2/3 x 1/8. That equals 0.08333... or 1/12.

Hope this helps!

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Select the function that's represented in the graph. Question 5 options: A) ƒ(x) = x2 – 3 B) ƒ(x) = –1∕2x2 – 3 C) ƒ(x) = –x2 – 3

Neporo4naja [7]

Answer:

Step-by-step explanation:

hello,

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ivann1987 [24]

Answer: Number 1 is 40 dollars

Step-by-step explanation:

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3 years ago

Sara drives 171 miles on 7.6 gallons of gas. She uses this information to calculate how many miles per gallon she can drive. Usi

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171 / 7.6 = 22.5 miles per gallon

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3 years ago

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Gnesinka [82]

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3 years ago

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

3 years ago