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3 years ago

5+30 = x+10 what is thiss

Mathematics

2 answers:

julia-pushkina [17]3 years ago

5 0

Answer:

Step-by-step explanation:

30+5=x+10

35=x+10

25=x

mrs_skeptik [129]3 years ago

4 0

Answer:

the answer is x=25 hope this helps

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Find −315÷134. Write your answer as a mixed number in simplest form.

kipiarov [429]

Answer:

$-2\frac{47}{134}$

Step-by-step explanation:

$-2\frac{47}{134} = -\frac{315}{134}$

$134$ can go into $-315$ twice at the most, so doubling $134$ will give us $268$ , which leaves us with $47$ left over to reach 315, which is why $47$ is the numerator. The remainder is ALWAYS the numerator.

I am joyous to assist you anytime.

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3 years ago

1. What is the rate of change for the equation 3x - 6y = 30 ?

vodka [1.7K]

Answer:

average rate of change is 1/2

Step-by-step explanation:

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3 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST!!!

Katyanochek1 [597]

Answer:

g(x) = (f-x)

Step-by-step explanation:

It's relection across the y axis

==> g(x) = (f-x)

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3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

Find the third side in simplest radical form:

larisa [96]

Answer:

x = √53

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

Step 1: Define

We are given a right triangle. We can use PT to solve for the missing length.

Step 2: Identify Variables

Leg a = 6

Leg b = x

Hypotenuse c = √89

Step 3: Solve for x

Set up equation: 6² + x² = (√89)²
Isolate x term: x² = (√89)² - 6²
Exponents: x² = 89 - 36
Subtract: x² = 53
Isolate x: x = √53

5 0

3 years ago