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Hatshy [7]
3 years ago
13

The price of a watch was increased by 7% to £1350. What was the price before the increase? Give your answer to the nearest penny

.
Mathematics
1 answer:
frutty [35]3 years ago
3 0

Answer:

1261.68

Step-by-step explanation:

1350 = the increased watch price= 107% of the original

1350= 1.07x

1261.68224299

Check:

7% of 1261.68224299 is 88.317757

1261.68224299 + 88.317757 = 1349.9 = 1350

Round:

1261.68224299  

To the penny= to the hundreth= 1261.68

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Solve log base 6 (x-6) - log base 6 (x + 4) = 2
Ray Of Light [21]

Answer:

no solutions

Step-by-step explanation:

Since the two terms have the same base, we are able to use the rule for subtracting logarithms:

log_{b}(x) - log_{b}(y) = log_{b}(\frac{x}{y} )

Therefore, the equation can be written as:

log_{6}(\frac{x-6}{x+4} )=2

By using the definition of a logarithm we can say that:

\frac{x-6}{x+4} = 6^{2}\\\frac{x-6}{x+4} = 36\\x -6 = 36x+144\\35x = -150\\x =-\frac{30}{7}

When plugging this solution in, you find that the term log_{6}(x-6) has x-6 evaluate to a number less than 0. This is not included in the domain of log functions, so -\frac{30}{7} is not a valid solution. This means that there are no solutions.

4 0
2 years ago
In a rectangular coordinate plane what is the distance between points (-3,0) and (3,8)
zheka24 [161]

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}


"d" represents the distance and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(3-(-3))^2+(8-0)^2}}\\\\ \mathsf{d=\sqrt{(3+3)^2+(8)^2}}\\\\ \mathsf{d=\sqrt{(6)^2+64}}\\\\ \mathsf{d=\sqrt{36+64}}\\\\ \mathsf{d=\sqrt{100}}\\\\ \underline{\mathsf{d=10}}


The answer is 10 uc.

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0
3 years ago
A tablet and a digital camcorder are both on sale for 30% off. The regular price of the tablet is $185. The regular price of the
Arlecino [84]

Answer:

129.50

Step-by-step explanation:

3 0
3 years ago
What is two plus two
Olenka [21]

Answer:

2+2=4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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