2 years ago

Keith determines the zeros of the function f(x) to be -6 and 5. What could be Keith's function?

Mathematics

1 answer:

marishachu [46]2 years ago

6 0

F(x)=(x+6)(x-5) or x^2+x-30

You might be interested in

the measure of angle s = 30 degrees, the measure of arc RS = 84 degrees and line RU is tangent to the circle at R. Find m angle

Paul [167]

Let O be the center of a circle. If <span>the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.
</span>
Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0} and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.
<span />

3 0

3 years ago

Read 2 more answers

Someone please help.

Leokris [45]

Answer:

See explanation

Step-by-step explanation:

1 = b (0,-2)

2 = b (0,1)

6 = a (3,0)

7 = a (-2,2)