Keith determines the zeros of the function f(x) to be -6 and 5. What could be Keith's function?

The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c

timurjin [86]

Answer:

a) 28

b)

Class Limits Class Boundaries Midpoint f Rf Cf

10 - 37 9.5-37.5 23.5 7 0.096 7

38 - 65 37.5-65.5 51.5 25 0.342 32

66 - 93 65.5-93.5 79.5 26 0.356 58

94 - 121 93.5-121.5 107.5 9 0.123 67

122 - 149 121.5-149.5 135.5 5 0.068 72

150 - 177 149.5-177.5 163.5 0 0.0 72

178 - 205 177.5-20.5 191.5 1 0.014 73

Total 73 1.0

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx

5 0

3 years ago

NEED HELP WITH THESE QUESTIONS

amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

$\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =$

Applying double C we have:

$\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =$

By definition of multiplication of powers of the same base we have to place the same base and add the exponents: $\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =$

Canceling common terms:

$\frac {mn ^ 5} {p ^ 4}$

Answer:

Option A

Question 2:

We should simplify the following expression:

$\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}$

So, we have:

$\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =$

Simplifying common terms:

$\frac {1} {y ^ 2z ^ 2}$

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

$r ^ 2 + 7r + 10$ : We look for two numbers that multiplied give 10 and added 7:

$(r + 5) (r + 2)$

$r ^ 2-5r-50:$ We look for two numbers that multiplied give -50 and added -5:

$(r-10) (r + 5)$

$3r-30 = 3 (r-10)$

Rewriting the given expression we have:

$\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =$

We simplify common terms in the numerator and denominator we have:

$(r + 2)$

Answer:

Option D

4 0

3 years ago

Read 2 more answers

Use suitable Identities and find ●( X - 5 ) ( x-5 ) ●( 3x +2 ) (3x -2 ) ●( 1+x )(1+x)

Nonamiya [84]

Answer:

$.$

Step-by-step explanation:

<h2>IdEnTiTy UsED</h2>

${x}^{2} - {y}^{2} = (x + y)(x - y)$

1)

$(x - 5)(x - 5)$

=(x-5)²

2)

$(3x - 2)(3x + 2)$

${(3 x)}^{2} - {(2)}^{2}$

$= 9 {x}^{2} - 4$

3)

$(1+x)(1+x)$

= (1+x)²

6 0

3 years ago

Find the area and please show the steps and explain. Thanks!

Anit [1.1K]

I'm pretty sure you just add all the numbers up so it would be 569.9 ft

3 0

2 years ago

Write an equation for the nth term of the geometric sequence. Then find the 7th term. 2,-6,18,-54,...

Sonja [21]

soln,

from the series,

a = 2

t2 = -6

r = t2/a

$= \frac{ - 6}{2}$

= -3

therefore, tn =

${ar}^{n - 1}$

$= {2 \times - 3}^{n - 1}$

now,

seventh term =

${2 \times - 3}^{7 - 1}$

$= {2 \times - 3}^{6}$

$= 2 \times 729$

$= 1458$

5 0

3 years ago