How many triangles are there that satisfy the conditions a = 3, b = 4, (alpha sign)= 76 degrees.

1 answer:

3 0

By Sine Rule

a/sinA = b/sinB = c/sinC

Given a = 3, b = 4, A = 76°

43sin76° = 4/sinB

==> sinB = 1.195380945

But sine function is only defined in the range [-1, 1], so there's no solution.

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