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Lana71 [14]
3 years ago
5

The data below show the numbers of hours Mrs. Diaz volunteered at the library each month

Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

A. 4.5

Step-by-step explanation:

Given:

20, 12, 27, 23, 18, 20, 30, 26

Mean = 22

Required:

Calculate the Mean Absolute Deviation (M.A.D)

Since, we have the mean; we start calculating M.A.D by subtracting the mean from each data

20 - 22 = -2

12 - 22 = -10

27 - 22 = 5

23 - 22 = 1

18 - 22 = -4

20 -22 = -2

30 - 22 = 8

26 - 22 = 4

The we find absolute value of the result above

|-2| = 2

|-10| = 10

|5| = 5

|1| = 1

|-4| = 4

|-2| = 2

|8| = 8

|4| = 4

Lastly, we calculate the mean of the above to give M.A.D

M.A.D = \frac{2 + 10 + 5 + 1 + 4 + 2 + 8 + 4}{8}

M.A.D = \frac{36}{8}

M.A.D = 4.5

Option A is correct.

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3 years ago
What is the slope of all lines parallel to the line 4x-5y+-1?
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Given equation of the line ,

\implies 4x - 5y +(-1) = 0

Simplify ,

\implies 4x - 5y - 1 = 0

Transpose terms to RHS ,

\implies 5y = 4x - 1

Divide both sides by 5 ,

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5 0
3 years ago
Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b
kramer

Answer:

(a)

\bar x = 0.0075

s = 0.0049

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

n = 8

\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}

Solving (a):

First, calculate the difference between the recorded TBBMC for both operators:

\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 &{|1 - 2|} &0.003 & 0.015 & 0.006 & 0.004 & 0.002 & 0.010 & 0.005 & 0.015 \ \end{array}

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

\bar x = \frac{\sum x}{n}

\bar x = \frac{0.003 + 0.015 + 0.006 + 0.004 + 0.002 + 0.010 + 0.005 + 0.015}{8}

\bar x = \frac{0.06}{8}

\bar x = 0.0075

Next, calculate the standard deviation (s).

This is calculated using:

s = \sqrt{\frac{\sum (x - \bar x)^2}{n}}

So, we have

s = \sqrt\frac{(0.003 - 0.0075)^2 + (0.015 - 0.0075)^2+ (0.006- 0.0075)^2+ ....... + (0.005- 0.0075)^2+ (0.015- 0.0075)^2 }{8}s = \sqrt\frac{0.00019}{8}

s = \sqrt{0.00002375

s = 0.0049

Solving (b):

Of the given options (A - E), option B is correct because the sample is actually too small

6 0
3 years ago
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