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4 years ago

8

A small company did an analysis of their pay scale versus years of experience and found that the line of best fit was y=2035.6x

+ 36000.what does the 36,000 mean in the context of the problem

2 answers:

vodka [1.7K]4 years ago

7 0

Answer:B.

They had 0 years of experience.

Step-by-step explanation:

PtichkaEL [24]4 years ago

3 0

X stands for the number of years experience . y = 36000 when x = 0 years experience, so the 36000 is the starting salary for a new employee.

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$x=-9,\:x=1$

Step-by-step explanation:

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2 years ago

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3 years ago

Question 20 points if correct

Vlada [557]

Answer:

B = 155° , C = 25° , D = 155°

Step-by-step explanation:

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4 years ago

Read 2 more answers

If we assume the population of Grand Rapids is growing at a rate of approximately 4% per decade, we can model the population fun

saw5 [17]

Answer:

The average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

Step-by-step explanation:

The given function is

$P(t)=181843(1.04)^{(\frac{t}{10})}$

where, P(t) is population after t years.

At t=5,

$P(5)=181843(1.04)^{(\frac{5}{10})}=185444.20$

At t=6,

$P(6)=181843(1.04)^{(\frac{6}{10})}=186172.95$

At t=7,

$P(7)=181843(1.04)^{(\frac{7}{10})}=186904.57$

At t=8,

$P(8)=181843(1.04)^{(\frac{8}{10})}=187639.06$

At t=9,

$P(9)=181843(1.04)^{(\frac{9}{10})}=188376.44$

At t=10,

$P(10)=181843(1.04)^{(\frac{10}{10})}=189116.72$

The rate of change of P(t) on the interval $[x_1,x_2]$ is

$m=\frac{P(x_2)-P(x_1)}{x_2-x_1}$

Using the above formula, the average rate of change of the population on the intervals [ 5 , 10 ] is

$m=\frac{P(10)-P(5)}{10-5}=\frac{189116.72-185444.20}{5}=734.504$

The average rate of change of the population on the intervals [ 5 , 9 ] is

$m=\frac{P(9)-P(5)}{9-5}=\frac{188376.44-185444.20}{4}=733.06$

The average rate of change of the population on the intervals [ 5 , 8 ] is

$m=\frac{P(8)-P(5)}{8-5}=\frac{187639.06-185444.20}{3}=731.62$

The average rate of change of the population on the intervals [ 5 , 7 ] is

$m=\frac{P(7)-P(5)}{7-5}=\frac{186904.57-185444.20}{2}=730.185$

The average rate of change of the population on the intervals [ 5 , 6 ] is

$m=\frac{P(6)-P(5)}{6-5}=\frac{186172.95-185444.20}{1}=728.75$

Therefore the average rate of change of the population on the intervals [ 5 , 10 ] , [ 5 , 9 ] , [ 5 , 8 ] , [ 5 , 7 ] , and [ 5 , 6 ] are 734.504, 733.06, 731.62, 730.185 and 728.75 respectively.

7 0

4 years ago

A plain pizza cost $8.35. Additional toppings cost $0.95 each. Which equation can be used to represent the cost of a pizza, y, w

Yakvenalex [24]

Answer: y=0.95x+8.35

Step-by-step explanation: Hi there.

We can use the equation y=mx+b, where

y=the result (in this case the cost of the pizza)

m=the slope (how much each topping costs)

x=input value (how many kinds of toppings the pizza has)

b=initial value (how much the plain pizza costs)

The toppings cost $0.95, and the value of the plain pizza is $8.35

So the equation is: y=0.95x+8.35.

Have a nice day! :)

7 0

3 years ago