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Kryger [21]
3 years ago
8

What are the similarities and differences between these data sets in terms of their centers and their variability?

Mathematics
1 answer:
balu736 [363]3 years ago
3 0

The median of data set A is less that the median in data set B and the range of data set A is greater than the range of data set B

Sorry if I get it wrong; please rate my answer

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1. Separate the number 58 into three parts so
Anika [276]

Answer:

2nd number = 13

First number = 15

3rd number = 30

Step-by-step explanation:

Let

2nd number = 1/2x - 2

First number = 1/2x

3rd number = x

Total = 58

x + 1/2x + 1/2x - 2 = 58

x + x+x/2 = 58 + 2

x + 2/2x = 60

x + x = 60

2x = 60

x = 60/2

= 30

x = 30

2nd number = 1/2x - 2

= 1/2*30 - 2

= 15 - 2

= 13

First number = 1/2x

= 1/2*30

= 15

3rd number = x

= 30

6 0
3 years ago
Consider the algebraic equation x + 3 = 9.
astraxan [27]

Answer:

isn't it only one

Step-by-step explanation:

Because 6+3=9

5 0
3 years ago
Solve 16t2 - 96t + 48 = 0.
velikii [3]

Answer:

the question is not written correctly 16t2 can't be used in the equation

Step-by-step explanation:

do it it correctly you need to combine the like numbers, subtract the 48 from both sides and then divide the number with the t to both sides.

8 0
3 years ago
Read 2 more answers
Number 14 on my integrated geometry test
FinnZ [79.3K]

Answer:

C. 21

Step-by-step explanation:

\cos \: 30 \degree =  \frac{x}{24} \\  \\  \frac{ \sqrt{3} }{2}   = \frac{x}{24} \\  \\ x =  \frac{24 \sqrt{3} }{2}  \\  \\ x = 12 \sqrt{3}  \\  \\   x = 20.7846097 \\  \\ x \approx \: 21

8 0
3 years ago
Read 2 more answers
For each of the figures, write an absolute value equation to satisfy the given solution set.
Valentin [98]

Answer:

|x-1|=5

Step-by-step explanation:

From the diagram you can see that the solutions of the equation are x_1=-4 and x_2=6

1. Find the midpoint between -4 and 6:

1/2(-4+6)=1

2. Find the distance between points x=1 and x=6 (or between x=1 and x=-4):

d=6-1=5

3. Writhe an absolute value equation (the distanse from endpoints x_1=-4 and x_2=6 to the midpoint x=1 is equal 5):

|x-1|=5

7 0
4 years ago
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