All categories

3 years ago

Se desean plantar 361 plantas de limón, en un terreno cuadrado, de manera que en cada fila queden a un metro de distancia.

Mathematics

1 answer:

Mila [183]3 years ago

5 0

Respuesta:

Explicación paso a paso:

Si se van a plantar 361 limoneros en un campo cuadrado;

Entonces, el número de plantas en cada fila debe ser el mismo por columna;

Sea el número de plantas por hilera = x

Número total de plantas = x²

361 = x²

Saca la raíz cuadrada de ambos lados

√361 = √x²

19 = x

Número de plantas por hilera = 19

You might be interested in

The low temperature last week in Iceland was-2.25. The low temperature this week was 1.25. What was the change in temperature fr

viktelen [127]

Answer:

The change in temperature from last week to this week=3.5

Step-by-step explanation:

To get the change in temperature from last week to this week, we need to take last week's temperature and subtract it from this week's temperature.

For example;

Change in temperature=This week's temperature-last week's temperature

where;

This week's temperature=-2.25

last week's temperature=1.25

replacing;

Change in temperature=(1.25)-(-2.25)=1.25+2.25=3.5

The change in temperature from last week to this week=3.5

6 0

3 years ago

_384<br> What is the square root of 384

sp2606 [1]

Answer:

19.5959179423

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st

Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so $\mu = 0.5, \sigma = 0.05$ .