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oee [108]
2 years ago
8

Is x = 0 a valid potential solution to the equation log(x + 2) + log(x + 5) = 1? (You don't need to solve this equation, just de

termine if x = 0 is a valid solution) Question 22 options: No, because log(0) is undefined. No, because the logarithm of a negative value is undefined. It can't be determined from the information given. Yes, since log(2) and log(5) both exist as valid values for the logarithm.
Mathematics
1 answer:
Xelga [282]2 years ago
8 0

Answer:

Yes, since log(2) and log(5) both exist as valid values for the logarithm.

didnt check if ur equation is correct though

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6 1/4 ft = how many yards
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2.083333 yards are in 6 1/4 feet


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3 years ago
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Are the following lines parallel? <br><br> y = -3x + 1 <br><br> y = 4 - 3x
PIT_PIT [208]

Answer:

Simple! The answer is yes.

Step-by-step explanation:

Simply put the equations into Desmos graphing calculator and it will show you that the equations are parallel. :))

4 0
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Determine the number of ways to distribute 10 orange drinks, 1 lemon drink, and 1 lime drink to four thirsty students so that ea
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each student gets 3 drinks, make sure the lemon and lime are in different groupings

Step-by-step explanation:

7 0
3 years ago
X-1<br> 1<br> X+4<br> +<br> 2x+1<br> =<br> x-2<br> 2x²-3x-2
kiruha [24]

Answer:

x = 2π3

Step-by-step explanation:

csc(x)csc(x) , x=πx=π

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cot(3x)cot(3x) , x=2π3

Hope this helps :)

8 0
3 years ago
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]
matrenka [14]

Answer:

Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]

Step-by-step explanation:

We are given that a function

f(x)=ln(x)

Interval [1,5]

The given function is defined on this interval.

Hypothesis of Mean Value Theorem:

(1) Function is continuous on interval [a,b]

(2)Function is defined on interval (a,b)

From the graph we can see that

The function is continuous on [1,5] and differentiable at(1,5).

Hence, the function satisfies the hypothesis of the Mean Value Theorem.

5 0
3 years ago
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