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oee [108]
2 years ago
8

Is x = 0 a valid potential solution to the equation log(x + 2) + log(x + 5) = 1? (You don't need to solve this equation, just de

termine if x = 0 is a valid solution) Question 22 options: No, because log(0) is undefined. No, because the logarithm of a negative value is undefined. It can't be determined from the information given. Yes, since log(2) and log(5) both exist as valid values for the logarithm.
Mathematics
1 answer:
Xelga [282]2 years ago
8 0

Answer:

Yes, since log(2) and log(5) both exist as valid values for the logarithm.

didnt check if ur equation is correct though

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What is the domain of the function in the graph?
Tpy6a [65]
The answer is A.
D= 6<=x<=11
8 0
4 years ago
Yolanda's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Yolanda $5.20 per pound, and t
MAXImum [283]

Answer:

78 pounds

Step-by-step explanation:

Let's say Yolanda makes a pounds of Type A coffee and b pounds of Type B coffee. Since the total number of pounds is 130, we can write the equation:

a + b = 130

We know the cost of Type A coffee is $5.20/lb and the cost of Type B coffee is $4.05/lb, so since the total cost is $586.30, we can write:

5.20a + 4.05b = 586.30

We can now solve the system of equations:

a + b = 130

5.20a + 4.05b = 586.30

Manipulate the first equation by subtracting b from both sides:

a + b = 130

a = 130 - b

Substitute 130 - b for a in the second equation:

5.20a + 4.05b = 586.30

5.20 * (130 - b) + 4.05b = 586.30

676 - 5.20b + 4.05b = 586.30

Move the terms with b to one side:

1.15b = 89.70

b = 78

Thus, Yolanda used 78 pounds of Type B coffee.

<em>~ an aesthetics lover</em>

7 0
3 years ago
Multiply 631.6 by 0.8​
pentagon [3]

Answer: multiply 631.6 by 0.8​ = 505.28

3 0
3 years ago
At what price must I sell a motor car costing £2680 to make a gain of 5% on the cost? Please help
Papessa [141]
So 2680 divided by 100 is 26.80 which is 1%, times 26.80 by 5 to get 5% = £134, £2680+134= £2814
3 0
4 years ago
Determine the value(s) for which the rational expression 2x^2/6x is undefined. If there's more than one value, list them separat
Dmitry [639]

Answer:

0

Step-by-step explanation:

Hello, dividing by 0 is not defined. so

\dfrac{2x^2}{6x}

is defined for x different from 0

This being said, we can simplify by 2x

\dfrac{2x^2}{6x}=\dfrac{2x*x}{3*2x}=\dfrac{1}{3}x

and this last expression is defined for any real number x.

Thank you

4 0
3 years ago
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