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notka56 [123]
3 years ago
15

5 - x/3 for x = -3 Evaluate the expression

Mathematics
1 answer:
Vladimir [108]3 years ago
6 0
The answer is 6. When x is -3 then you divide -3 by 3 and the quotient is -1. So 5-(-1) is also equal to 5+1 which equals 6
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The total bill for drinks and a pizza for three people is $14.90 before tax. The group wants to leave a 15% tip on the cost of t
andreyandreev [35.5K]

Answer:

$2.24

Step-by-step explanation:

Since we are trying to find a percentage of something, we can multiply whatever we're trying to find a percentage from by 0.X where X is equal to the number of the percentage. So in this case it's 15%. We can multiply $14.90 by 0.15 and we get 2.23500. Since we cannot have 2.235 dollars, we must round up decimal places.

The tip would be 2 dollars and 24 cents. ($2.24).

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3 years ago
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Roman55 [17]
Hmmm I think it may be the third?
7 0
3 years ago
Grant finds the difference of 360 and 127 as shown. What is Grant's
pychu [463]

Answer:

D. Grant did not regroup the 4 tens when he  subtracted 7.

Step-by-step explanation:

In the process of subtraction, regrouping is important so that each digit in the given numbers are placed appropriately before the required arithmetic operation is performed.

The correct step to Grant's solution are:

360 - 100 = 260

260 - 20 = 240

240 - 7 = 233

Grant's final answer ought to have been 233.

Going through his solution, he made a mistake while subtracting 7 from 240. He failed to regroup the 4 tens when he  subtracted 7 from 240. Thus the essence of his wrong answer.

6 0
3 years ago
Please help me answer this question
strojnjashka [21]

Answer:

  • modulus: 3√2
  • argument: -3π/4  (or 5π/4)

Step-by-step explanation:

The modulus is the magnitude of the complex number; the argument is its angle (usually in radians).

__

<h3>rectangular form</h3>

The complex number can be cleared from the denominator by multiplying numerator and denominator by its conjugate:

  \dfrac{-9+3i}{1-2i}=\dfrac{(-9+3i)(1+2i)}{(1-2i)(1+2i)}=\dfrac{-9+3i-18i-6}{1+4}=-3-3i

<h3>polar form</h3>

The magnitude of this number is the root of the sum of the squares of the real and imaginary parts:

  modulus = √((-3)² +(-3)²) = 3√2

The argument is the arctangent of the ratio of the imaginary part to the real part, taking quadrant into consideration.

  arg = arctan(-3/-3) = -3π/4  or  5π/4 . . . . radians

__

  modulus∠argument = (3√2)∠(-3π/4)

3 0
2 years ago
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