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Luda [366]
3 years ago
15

An angle measures 130° less than the measure of its supplementary angle. What is the measure of each angle?

Mathematics
1 answer:
seropon [69]3 years ago
3 0

Answer:

Angle one is 130 degrees and angle two is 50 degrees

Step-by-step explanation:

You can get this answer by knowing that supplementary angles equal 180 degrees in total. So if one angle is 130 degrees less you take that and subtract it from 180 to get 50 degrees as the second angle.

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Solve for x using the given diagram
blagie [28]

Answer:

<h2>x = 1</h2>

Step-by-step explanation:

Look a t the picture.

The triangles on the picture are similar.

Therefore the sides are in proportion:

\dfrac{8x}{10}=\dfrac{4}{5x}              <em>cross multiply</em>

(8x)(5x)=(4)(10)

40x^2=40           <em>divide both sides by 40</em>

x^2=1\to x=\sqrt1\\\\x=1

7 0
3 years ago
Find abc !!!!!!!! !!!!!
KonstantinChe [14]

Answer:

58 degreess

3x+11=4x-5

-3x      -3x

11=x-5

+5   +5

16=x

x=6

3(6)+11

18+11

29

29*2

58

Step-by-step explanation:

8 0
2 years ago
Factor 75t2 + 12.<br> 3(5t + 2)2<br> 3(25+2 +4)<br> 3(251-4)
frosja888 [35]

Answer:

75t^2+12=3(25t^2+4)

Option C)

Step-by-step explanation:

Here we are given with the expression 75t^2+12

The GCF of 75t^2 and 12 is 3

Hence we take 3 as GCF and bring it in front of the bracket.

3(25t^2+4)

It can not be factorise furthure  as there is no GCF of 25 and  also there is no rule for sum of squares so that we may apply it on this. Hence the answer would be

3(25t^2+4)

Option C)

4 0
3 years ago
Help. Please look at the picture. Thanks.
densk [106]

Answer:

Monday: 2 hours

Tuesday: 7 miles

Thursday: 27 miles

Friday: 2 hours

Step-by-step explanation:

Monday: 16 divided by 8 = 2

Tuesday: 21 divided by 3 = 7

Thursday: 9 x 3 = 27

Friday: 16 divided by 8 = 2

I hoped this helped

4 0
2 years ago
What does n^9/n^5 equal
vovangra [49]

Answer:

n^4

Step-by-step explanation:

Rule:

\dfrac{a^m}{a^n} = a^{m - n}

Your problem:

\dfrac{n^9}{n^5} = n^{9 - 5} = n^4

4 0
3 years ago
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