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Westkost [7]
3 years ago
12

May someone help me with this factor equation?

Mathematics
1 answer:
raketka [301]3 years ago
6 0

Answer:

\frac{x^2+8x+9}{(x+3)(x-1)}

Step-by-step explanation:

\frac{2x}{x^2+2x-3} + \frac{x+3}{x-1} ← factor the denominator of first fraction

= \frac{2x}{(x+3)(x-1)}  + \frac{x+3}{x-1}

Before adding we require the denominators to be the same

Multiply numerator/denominator of second fraction by (x + 3)

= \frac{2x}{(x+3)(x-1)} + \frac{(x+3)(x+3)}{(x+3)(x-1)}

Add the numerators leaving the common denominator ( LCD = (x + 3)(x - 1) )

= \frac{2x+(x+3)(x+3)}{(x+3)(x-1)} ← expand factors on numerator using FOIL

= \frac{2x+x^2+6x+9}{(x+3)(x-1)}

= \frac{x^2+8x+9}{(x+3)(x-1)}

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