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2 years ago

May someone help me with this factor equation?

Mathematics

1 answer:

raketka [301]2 years ago

6 0

Answer:

$\frac{x^2+8x+9}{(x+3)(x-1)}$

Step-by-step explanation:

$\frac{2x}{x^2+2x-3}$ + $\frac{x+3}{x-1}$ ← factor the denominator of first fraction

= $\frac{2x}{(x+3)(x-1)}$ + $\frac{x+3}{x-1}$

Before adding we require the denominators to be the same

Multiply numerator/denominator of second fraction by (x + 3)

= $\frac{2x}{(x+3)(x-1)}$ + $\frac{(x+3)(x+3)}{(x+3)(x-1)}$

Add the numerators leaving the common denominator ( LCD = (x + 3)(x - 1) )

= $\frac{2x+(x+3)(x+3)}{(x+3)(x-1)}$ ← expand factors on numerator using FOIL

= $\frac{2x+x^2+6x+9}{(x+3)(x-1)}$

= $\frac{x^2+8x+9}{(x+3)(x-1)}$

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