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Fofino [41]
4 years ago
9

A pair of equations is shown below: y = 8x − 9 y = 4x − 1 Part A: Explain how you will solve the pair of equations by substituti

on or elimination. Show all the steps and write the solution. (5 points) Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer. (5 points) HELP 69 PTS
Mathematics
1 answer:
insens350 [35]4 years ago
5 0
Here's the first part:

y = 8x - 9  --(i)
y = 4x - 1 -- (ii)

then in eqn( i),
 4x - 1 = 8x -9   (from eqn( ii) )
 -1 +9 = 8x -4x
8 = 4x
x =2 

then in eqn (i),
y = 8*2 -9
   = 16 -9
   = 7

The 2nd part:

When these two equations are graphed, at point (2,7) the lines representing the two equations intersect because these values (2,7) satisfies the given equations.

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2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

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Here, a = 2; b = 3; c = - 9

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$ \implies x = \frac{-3 \pm 9}{4} $

We get two values of 'x', viz.,

x = $ \frac{-3 + 9}{4} $ and $ \frac{- 3 - 9}{4} $

$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

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3 years ago
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