To answer the question above, evaluate the number of cookies each of them placed on a tray. The calculations are shown below,
Ronny C1 = 0.15 x 20 = 3
Celina C2 = 3
Jack C3 = 0.30 x 20 = 6
Michelle C4 = 20 - (3 + 3 + 6) = 8
From the calculation above, <em>Michelle</em> placed the most number of brownies on the tray.
8mm bc a=lw. If a=32 and l=4, you get 4w=32. Then, solve for w.
Answer:
non mutually exclusive event
Step-by-step explanation:
im not sure on this tho
![[n][n+8]=0](https://tex.z-dn.net/?f=%5Bn%5D%5Bn%2B8%5D%3D0)
if either or both of
![[n]](https://tex.z-dn.net/?f=%5Bn%5D)
and
![[n+8]](https://tex.z-dn.net/?f=%5Bn%2B8%5D)
are 0, i.e. if one or both of
and
are even. But both will be even if
is even, and odd otherwise, so any even
will be a solution, e.g.
.
y = mx + b
The b is always the y-intercept, so that means
y = mx + b
y = 6x + 8
The answer is C. (0, 8)!
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