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Andre45 [30]
3 years ago
5

Carmine mixes 2.8 pounds of cashews with almonds to make a trail mix. He divides the trail mix into 5 equal portions. Each porti

on weighs 1.5 pounds. Which equation and solution shows the total amount of almonds he used in the mixture? One-fifth (2.8 + a) = 1.5 (5); a = 34.7 pounds of almonds One-fifth (2.8 + a) = 1.5; a = 4.7 pounds of almonds One-fifth (2.8 + a) = 1.5 (5); a = 4.7 pounds of almonds One-fifth (2.8 + a) = 1.5; a = 34.7 pounds of almonds
Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

I think its choice C

Step-by-step explanation:

Because it makes more sense to me

5 * 1.5 to get 7.5, which is total pounds

7.5 - 2.8 to get how many almonds

= 4.7

Choice C makes the most sense to get that answer

i'm only in 5th grade so tell me if i'm wrong ill be ok with that

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What is the distance between the following coordinates? Show work.
miss Akunina [59]

Answer:

\huge{ \boxed{ \bold{ \tt{2 \sqrt{26}}}  \:  \: \text{units} } }

<h3>♁ Question :</h3>
  • Find the distance between ( 5 , -6 ) and ( 3 ,4 ).

<h3>♁ Step by step explanation:</h3>

Let the points be A and B. Now,

  • Let, A ( 5 , -6 ) ⇢ ( x₁ , y₁ )
  • Let, B ( 3 , 4 ) ⇢ ( x₂ , y₂ )

Use the distance formula to determine the distance between A ( 5 , -6 ) and B ( 3 , 4 ).

\boxed{ \underline{ \sf{distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}}

Substitute the actual value of the points into the distance formula and then simplify.

\dashrightarrow{ \sf{ \sqrt{ {(3 - 5)}^{2} +  {(4 - ( - 6))}^{2}  } }}

Remember : The positive and negative integer are always subtracted but posses the sign of the bigger integer.

\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2}  +  {(4 - ( - 6))}^{2} } }}

Remember : ( - ) × ( - ) = ( + )

\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} +  {(4 + 6)}^{2}  } }}

Add the numbers : 4 and 6

\longrightarrow{ \sf{ \sqrt{ {( - 2)}^{2}  +  {(10)}^{2} } }}

Evaluate the power

\longrightarrow{ \sf{ \sqrt{4 + 100}}}

Add the numbers : 4 and 100

\dashrightarrow{ \sf{ \sqrt{104}}}

\dashrightarrow{ \boxed{ \sf{2 \sqrt{26} }}} units

Therefore , The distance between ( 5 , -6 ) and ( 3 , 4 ) is \sf{2 \sqrt{26}} units .

And we're done!

Hope I helped!

Have a wonderful time ! シ

~TheAnimeGirl

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3 years ago
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