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hjlf
3 years ago
5

Please help with a, b, and c!!

Mathematics
2 answers:
ipn [44]3 years ago
8 0
A. (3j - 5)(3j + 5)
    3j(3j + 5) - 5(3j + 5)
    3j(3j) + 3j(5) - 5(3j) - 5(5)
    9j² + 15j - 15j - 25
    9j² - 25

b. (4h + 5)²
    (4h + 5)(4h + 5)
    4h(4h + 5) + 5(4h + 5)
    4h(4h) + 4h(5) + 5(4h) + 5(5)
    16h² + 20h + 20h + 25
    16h² + 40h + 25

c. (g - 2)²(g + 2)²
    (g - 2)(g - 2)(g + 2)(g + 2)
    (g(g - 2) - 2(g - 2))(g(g + 2) + 2(g + 2))
    (g(g) - g(2) - 2(g) + 2(2))(g(g) + g(2) + 2(g) + 2(2))
    (g² - 2g - 2g + 4)(g² + 2g + 2g + 4)
    (g² - 4g + 4)(g² + 4g + 4)
    g²(g² + 4g + 4) - 4g(g² + 4g + 4) + 4(g² + 4g + 4)
    g²(g²) + g²(4g) + g²(4) - 4g(g²) - 4g(4g) - 4g(4) + 4(g²) + 4(4g) + 4(4)
    g⁴ + 4g³ + 4g² - 4g³ - 16g² - 16g + 4g² + 16g + 16
    g⁴ + 4g³ - 4g³ + 4g² - 16g² + 4g² - 16g + 16g + 16
    g⁴ - 12g² + 4g² + 16
    g⁴ - 8g² + 16
padilas [110]3 years ago
5 0
(a). 
The product of two binomials is sometimes called FOIL.
It stands for ...

       the product of the First terms                (3j  x  3j)
plus
       the product of the Outside terms          (3j  x  5)
plus
       the product of the Inside terms            (-5  x  3j)
plus
       the product of the Last terms                (-5  x  5)

FOIL works for multiplying ANY two binomials (quantities with 2 terms).

Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .

Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.

Whenever you have     

              (the sum of two things) x (the difference of the same things)

the product is going to be

                 (the first thing)²  minus  (the second thing)² .

So in (a), that'll be      (3j)² - (5)²  =  9j² - 25 .

You could find the product with FOIL, or with this easier tool.
______________________________

(b).
This is the square of a binomial ... multiplying it by itself.  So it's
another product of 2 binomials, that both happen to be the same:

                            (4h + 5) x (4h + 5)  .

You can do the product with FOIL, or use another little tool:

The square of a binomial        (4h + 5)²    is ...

         the square of the first term               (4h)²
plus
         the square of the last term                (5)²
plus
         double the product of the terms      2 · (4h · 5)
________________________________

(c).
Use the tool I gave you in part-a . . . twice .

The product of the first 2 binomials is           (g² - 4) .

The product of the last 2 binomials is also    (g² - 4) .

Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .

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At the state fair 4 employees were paid $8.20 an hour to work at a corn-dog stand. They worked for 10 hours at regular pay and t
Katen [24]

Answer:

<u>The four employees earned $ 452.80 in total</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Hour rate = $ 8.20

Overtime hour rate = $ 2.20 extra

Regular hours = 10

Overtime hours = 3

Number of employees = 4

2. How much money did they earn in total?

Let's find out the individual pay for an employee and then we'll calculate the pay for the 4 employees:

Individual pay = 10 * 8.20 + 3 * 10.40

Individual pay = $ 113.20

Total pay = Individual pay * 4

Total pay = 113.20 * 4

<u>Total pay = $ 452.80 </u>

6 0
3 years ago
Which of the following would you most likely measure in kilograms?
garri49 [273]

Answer:

The mass of a longhorn cow.

Step-by-step explanation:

Kilograms will measure mass, not length, so we are left between two options. Kilograms would be used for heavier objects, so between a paper clip (which would be likely measured in grams,) and the longhorn, the cow would be what you would measure in kilograms.

5 0
3 years ago
Let A and B be two events in a sample space S such that
klasskru [66]
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)

</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
5 0
3 years ago
The result of adding a complex number to its conjugate is “an integer/a pure imaginary number/a real number/a whole number” and
sineoko [7]

Answer:

If Z is a complex number:

Z = a + b*i

where a and b are real numbers, and i is an imaginary number.

Then "a" is the real part.

"b*i" is the imaginary part.

The conjugate of Z is:

Zc = a - b*i

So the sign of the imaginary part changes.

Then:

Sum:

Z + Zc = (a + bi) + (a - bi) = 2*a + 0 = 2*a

and remember that a is a real number, then 2*a is also a real numer.

The correct answer is "A real number".

Difference:

Z - Zc = (a + bi) - (a - bi) = 2b*i

and this is a pure imaginary number, so here the correct answer is: "a pure imaginary number"

6 0
3 years ago
Write an expression that shows how to multiply 7x256 using expanded form and distributive property
Diano4ka-milaya [45]

7(200 + 50 + 6) = (7 x 200) + (7 x 50) + (7 x 6) = 1,400 + 350 + 42 = 1,792

3 0
3 years ago
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