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hjlf
3 years ago
5

Please help with a, b, and c!!

Mathematics
2 answers:
ipn [44]3 years ago
8 0
A. (3j - 5)(3j + 5)
    3j(3j + 5) - 5(3j + 5)
    3j(3j) + 3j(5) - 5(3j) - 5(5)
    9j² + 15j - 15j - 25
    9j² - 25

b. (4h + 5)²
    (4h + 5)(4h + 5)
    4h(4h + 5) + 5(4h + 5)
    4h(4h) + 4h(5) + 5(4h) + 5(5)
    16h² + 20h + 20h + 25
    16h² + 40h + 25

c. (g - 2)²(g + 2)²
    (g - 2)(g - 2)(g + 2)(g + 2)
    (g(g - 2) - 2(g - 2))(g(g + 2) + 2(g + 2))
    (g(g) - g(2) - 2(g) + 2(2))(g(g) + g(2) + 2(g) + 2(2))
    (g² - 2g - 2g + 4)(g² + 2g + 2g + 4)
    (g² - 4g + 4)(g² + 4g + 4)
    g²(g² + 4g + 4) - 4g(g² + 4g + 4) + 4(g² + 4g + 4)
    g²(g²) + g²(4g) + g²(4) - 4g(g²) - 4g(4g) - 4g(4) + 4(g²) + 4(4g) + 4(4)
    g⁴ + 4g³ + 4g² - 4g³ - 16g² - 16g + 4g² + 16g + 16
    g⁴ + 4g³ - 4g³ + 4g² - 16g² + 4g² - 16g + 16g + 16
    g⁴ - 12g² + 4g² + 16
    g⁴ - 8g² + 16
padilas [110]3 years ago
5 0
(a). 
The product of two binomials is sometimes called FOIL.
It stands for ...

       the product of the First terms                (3j  x  3j)
plus
       the product of the Outside terms          (3j  x  5)
plus
       the product of the Inside terms            (-5  x  3j)
plus
       the product of the Last terms                (-5  x  5)

FOIL works for multiplying ANY two binomials (quantities with 2 terms).

Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .

Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.

Whenever you have     

              (the sum of two things) x (the difference of the same things)

the product is going to be

                 (the first thing)²  minus  (the second thing)² .

So in (a), that'll be      (3j)² - (5)²  =  9j² - 25 .

You could find the product with FOIL, or with this easier tool.
______________________________

(b).
This is the square of a binomial ... multiplying it by itself.  So it's
another product of 2 binomials, that both happen to be the same:

                            (4h + 5) x (4h + 5)  .

You can do the product with FOIL, or use another little tool:

The square of a binomial        (4h + 5)²    is ...

         the square of the first term               (4h)²
plus
         the square of the last term                (5)²
plus
         double the product of the terms      2 · (4h · 5)
________________________________

(c).
Use the tool I gave you in part-a . . . twice .

The product of the first 2 binomials is           (g² - 4) .

The product of the last 2 binomials is also    (g² - 4) .

Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .

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How do I solve this equation? 3|13-2t|=15
Nikolay [14]
3 |13 - 2t | =15 ⇒ |13-2t| = 15\div3 ⇒ \boxed {|13-2t| = 5}

\hbox {We have two equations : 1. } |13-2t|=5 
                                               2.|13-2t|=-5

\hbox{The first: } ⇒ 13-2t=5 ⇒ 2t=13-5 ⇒ 2t=8 ⇒ \boxed {t=4}

\hbox { The second: } 13-2t=-5 ⇒ 2t=13-(-5)=18 ⇒ \boxed {t=9}
5 0
3 years ago
Read 2 more answers
What is the slope of a line that is perpendicular to the line y = x 4? the slope of the line is .
SIZIF [17.4K]

Answer:-1/4

Step-by-step explanation:

Take the negative of the reciprocal for perpendicular lines. In the case of no slope (y=number) replace y with x

7 0
2 years ago
In how many map squares did we spot more than 29 plant species
Katena32 [7]

Answer:

10 map squares.

Step-by-step explanation:

We have been given a histogram, which represents the plant species spotted in the animal reserve.

The x-axis represents the number of plant species and y axis represents the number of map squares.

We can see that 0 to 9 species are spotted in 1 map square.

10 to 19 and 20 to 29 plant species are spotted in 2 map squares.

To find the number of map squares that spot more than 29 plant species, we will count number of map squares that spot 30 to 49 plant species as 30 to 49 numbers are more than 29.

We can see from our histogram that 4 map squares spot 30 to 39 plant species and 6 map squares spot 40 to 49 plant species.

\text{Total number of map squares that spot more than 29 plant species}=4+6

\text{Total number of map squares that spot more than 29 plant species}=10

Therefore, 10 map squares spot more than 29 plant species.

5 0
3 years ago
Read 2 more answers
Help ‍♂️‍♂️‍♂️‍♂️‍♂️‍♂️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♀️‍♂️‍♂️‍♀️‍♀️‍♀️‍♂️‍♂️‍♂️‍♂️‍♂️
Sati [7]

Answer:

Step-by-step explanation:

then 380 and then add them

418

7 0
3 years ago
Read 2 more answers
Anybody know how to do # 14, 15, and 16? Would also be nice if yall told me if any of these were wrong
mote1985 [20]

Step-by-step explanation:

1. Right

2. Right

3. Right

4. Right

5. Right

6. Right

7. Its not properly visible sorry for this.

8. Its wrong

(\frac{1}{3} ) {}^{2}  =  \frac{1}{9}

9. Right

10. Its wrong

0.5 {}^{3}  = 0.125

11. Right

12. Its wrong.... Bcz square of minus is plus

- 9 {}^{2}  = 81

13. Right

14. According to the BODMAS rule..

15 - 7 \times 2 +  {2}^{3}

15 - 14 + 8

1 + 8 = 9

15.

(11 - 8) {}^{2}  - 2 \times 6

3 {}^{2}  - 12

9 - 12 =  - 3

16.

12 +  \frac{ {9}^{2} }{3}

12 +  \frac{81}{3}

12 + 27 = 39

<h3>Hope this helps u </h3>

... ✌️❤️

7 0
3 years ago
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