Answer:
5√3 X squared
Step-by-step explanation:
Individually work them out then put in back on the fraction and once you simplify it gives you the answer.
4x + 2 - 3x + 5 - 2(x + 5) = (2x - 5) + (3x + 4)
4x + 2 - 3x + 5 - 2x - 10 = 2x - 5 + 3x + 4
4x - 3x - 2x + 5 + 2 - 10 = 2x + 3x - 5 + 4
- x - 3 = 5x - 1
-x - 3 = 5x - 1 is the line above recopied
+x = +x
-3 = 6x - 1
<span> +1 = + 1 </span>
- 2 = 6x
- 2/6 = 6x/6
- 1/3 = x, the answer
To solve this problem you must apply the proccedure shown below:
1- You have that the equation of the line is:

Where
is the slope and
is the y-intercept.
2- Based on the information given in the problem, the lines
and
are parallel, which means that both have the same slope. Therefore, you can calculate the slope of
:


3- Use the coordinates of the point
to calculate the y-intercept:

4. Solve for
:

5. The equation of the line
is:

The answer is: 
3/5 is the answer. Difference means to subtract
Answer:
- P(t) = 100·2.3^t
- 529 after 2 hours
- 441 per hour, rate of growth at 2 hours
- 5.5 hours to reach 10,000
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
__
(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
__
(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
__
(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000