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Setler79 [48]
3 years ago
12

Which choice best represents the balance of a savings account at the end of 6 years if the simple interest earned each year is 6

.5% and the principal is $1,300?
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

$507.00.

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 6.5%/100 = 0.065 per year,

then, solving our equation

I = 1300 × 0.065 × 6 = 507

I = $ 507.00

The simple interest accumulated

on a principal of $ 1,300.00

at a rate of 6.5% per year

for 6 years is $ 507.00.

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How many solutions does the system have?
Maksim231197 [3]

Answer:

B. No solution

Step-by-step explanation:

y = 3x+9

y = 3x-7

Set the two equations equal since they are both equal to y

3x+9 = 3x-7

Subtract 3x from each side

3x+9-3x = 3x-7-3x

9 = -7

This is never true, so there are no solutions

3 0
4 years ago
Help me plz <br> what´s 1000×1000=<br> thanks!!!
inn [45]
The answer is 1,000,000
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=f%20%3D%28x%29%20%3D%20%5Cfrac%7Bx%7D%7B4%7D%20" id="TexFormula1" title="f =(x) = \frac{x}{4}
Inga [223]

Answer:

g(x) = \frac{x+3}{x-3}

Step-by-step explanation:

From the picture attached,

Given function is,

f(x) = x + 1

We have to find the value of g(x) if the composite function has been given as,

f[g(x)] = g(x) + 1 = \frac{2x}{(x-3)}

g(x) = \frac{2x}{(x-3)}-1

      = \frac{2x-(x-3)}{(x-3)}

      = \frac{(x+3)}{(x-3)}

Therefore, g(x) = \frac{x+3}{x-3} will be the answer.

5 0
3 years ago
Solve the equation. 2x squared-3x+1=0
natali 33 [55]

2x^2-3x+1=0\\\\2x^2-2x-x+1=0\\\\2x(x-1)-1(x-1)=0\\\\(x-1)(2x-1)=0\iff x-1=0\ \vee\ 2x-1=0\ \ \ \ |+1\\\\x=1\ \vee\ 2x=1\ \ \ |:2\\\\\boxed{x=1\ \vee\ x=0.5}

4 0
3 years ago
Exact = 50 Approximate = 45
Nikitich [7]

Answer:

Approximate of error = 11.11 % (Approx.)

Step-by-step explanation:

Given:

Exact value = 50

Approximate value = 45

Find:

Approximate of error

Computation:

Approximate of error = [(Exact value - Approximate value)/Approximate value]100

Approximate of error = [(50 - 45)/45]100

Approximate of error = [(5)/45]100

Approximate of error = [0.11111]100

Approximate of error = 11.11 % (Approx.)

3 0
3 years ago
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