The equation of c is an illustration of subject of formula
The equation of c in terms of r and t is c = r - 15/t
<h3>How to determine the equation?</h3>
The equation is given as:
t = 15/(r - c)
Cross multiply
t(r - c) = 15
Divide both sides by t
r - c = 15/t
Subtract r from both sides
-c = -r + 15/t
Multiply both sides by -1
c = r - 15/t
Take LCM
![c = \frac{rt - 15}{t}](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7Brt%20-%2015%7D%7Bt%7D)
Hence, the equation of c in terms of r and t is ![c = \frac{rt - 15}{t}](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%7Brt%20-%2015%7D%7Bt%7D)
Read more about subject of formula at:
brainly.com/question/10643782
It is a down shift of 3.
Also written as (x, y-3)
Answer:
-8/17
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-75-(-51))/(31-(-20))
m=(-75+51)/(31+20)
m=-24/51
m=-8/17
Answer:
0.125 = 125/1000
Step-by-step explanation:
<u>Corrected Question</u>
Suppose the value R(d) of d dollars in euros is given by
. The cost in dollars to purchase and ship n purses is given by P(n)=66n+23. Write a formula for the cost, Q(n) in euros to purchase and ship n purses.
Answer:
![Q(n)=\dfrac67(66n+23)](https://tex.z-dn.net/?f=Q%28n%29%3D%5Cdfrac67%2866n%2B23%29)
Step-by-step explanation:
The value R(d) of d dollars in euros is given by ![R(d)=\dfrac67 d](https://tex.z-dn.net/?f=R%28d%29%3D%5Cdfrac67%20d)
Therefore:
![R(1)=\dfrac67](https://tex.z-dn.net/?f=R%281%29%3D%5Cdfrac67)
![T$hat is, 1 dollars =\dfrac67$ euros](https://tex.z-dn.net/?f=T%24hat%20is%2C%201%20%20dollars%20%3D%5Cdfrac67%24%20euros)
The cost P(n) in dollars to purchase and ship n purses is given by:
![P(n) = 66n+23.](https://tex.z-dn.net/?f=P%28n%29%20%3D%2066n%2B23.)
Therefore, the cost, Q(n) in euros to purchase and ship n purses
![=\dfrac67 \cdot P(n)\\Q(n)=\dfrac67(66n+23)](https://tex.z-dn.net/?f=%3D%5Cdfrac67%20%5Ccdot%20P%28n%29%5C%5CQ%28n%29%3D%5Cdfrac67%2866n%2B23%29)