Question

8r 2 −5rt+2t 2 8, r, squared, minus, 5, r, t, plus, 2, t, squared from 4r^2+3rt-7t^24r 2 +3rt−7t 2 4, r, squared, plus, 3, r, t, minus, 7, t, squared

Answer 1

Answer:

$-4r^2 +8rt-9t^2$

Step-by-step explanation:

We want to subtract $8r^2 -5rt+2t^2$ from $4r^2+3rt-7t^2$

This is given as:

$4r^2+3rt-7t^2 -(8r^2 -5rt+2t^2)$

Open the bracket

$4r^2+3rt-7t^2 -8r^2 +5rt-2t^2$

Collect like terms

$4r^2 -8r^2 +5rt+3rt-7t^2-2t^2$

Simplify

$=-4r^2 +8rt-9t^2$

Therefore:

$4r^2+3rt-7t^2 -(8r^2 -5rt+2t^2) =-4r^2 +8rt-9t^2$