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m_a_m_a [10]
3 years ago
12

What is the value of p? x=1/4y^2

Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0

Answer:

The value of p is 1

Step-by-step explanation:

we know that

The standard form of the equation of a horizontal parabola is

(y - k)^{2}= 4p(x - h)

where

(h,k) is the vertex

p≠ 0

If p > 0, the parabola opens to the right, and if p < 0, the parabola opens to the left.

In this problem we have

x=\frac{1}{4}y^{2}

Convert to standard form

y^{2}=4x

The vertex is the point (0,0)

4p=4

p=1 -----> p > 0, the parabola opens to the right

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