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2 years ago

Which expression is equivalent to 7a³ (8a² + a)²-4a³? Simplify.

1 answer:

8 0

$7a³ (8a² + a)²-4a³ \\ \\ 7 {a}^{3}(8 { {a}^{2} + a)(8 {a}^{2} + a )} - 4 {a}^{3} \\ \\ 7 {a}^{3} ( {8a}^{2} (8 {a}^{2} + a ) + a(8 {a}^{2} + a ) - 4 {a}^{3} \\ \\ 7 {a}^{3} (64 {a}^{4} + 8{a}^{3} + 8 {a}^{3} + {a}^{2} ) - 4 {a}^{3} \\ \\ 7 {a}^{3} (64 {a}^{4} + 16 {a}^{3} + {a}^{2} ) - 4 {a}^{3} \\ \\ 448 {a}^{7} + 112 {a}^{6} + 7 {a}^{5} - 4 {a}^{3} \\ \\ {a}^{3} (448 {a}^{4} + 112 {a}^{3} + 7 {a}^{2} - 4).$

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Compare learning about functions to learning a new language. How are they similar

kow [346]

Answer: They are similar many ways.

Step-by-step explanation:

1. There is a law that guides both of them. Because each has a strick law.

2. They both need practice. Practice they say makes one perfect. When u practice both of them, you become familiar on how to use them.

3. The brain has to read meaning to either of the two to be able to be able to learn a pattern of learn.

4. Both language and functions are systems. They are made of different parts, language is made up of different words while function is made up of axioms which theorems.

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4 years ago

Ms. B is making snickerdoodle cookies. Her recipe uses one and a half teaspoons of cinnamon to make two dozen cookies. If she ne

Korvikt [17]

Answer:

First we must learn to dissect a question.

<h3>Explanation:</h3>

Part 1

We can list our facts first:

Every 2 dozen cookies takes 1.5 teaspoons of cinnamon to make
She needs 13 dozen cookies

She needs 13 dozen cookies. So (13/2)x 1.5 teaspoons

$6.5 \times 1.5 = 9.75 \: teaspoons$

She needs 9.75 teaspoons and 3 teaspoons make a tablespoon

So..

$9.75 \div 3 = 3 r0.75= 3tbsp \: and \: 0.75tsp$

7 0

2 years ago

If a translation of T-3,-8(x, y) is applied to square ABCD,<br> what is the y-coordinate of B?

borishaifa [10]

Square ABCD of the translation T-3,-8(x,y)

4 0

3 years ago

What is the answer to this question I can’t work it out Ni=n02(yi-yo)/t2

mr_godi [17]

Changing the subject of an equation involves solving for another variable in the equation

The equation of t is $t=\frac{\sqrt{y_i-y_o}}{N}$

<h3>How to change the subject of the equation</h3>

The equation is given as:

$N=\sqrt[2]{\frac{y_i-y_o}{t^2}}$

Rewrite the equation as:

$N=\sqrt{\frac{y_i-y_o}{t^2}}$

Evaluate the square root of t^2

$N=\frac{\sqrt{y_i-y_o}}{t}$

Multiply both sides by t

$Nt=\sqrt{y_i-y_o}$

Make t the subject, in the above equation

$t=\frac{\sqrt{y_i-y_o}}{N}$

Hence, the equation of t is $t=\frac{\sqrt{y_i-y_o}}{N}$

Read more about subject of formula at:

brainly.com/question/657646

6 0

2 years ago

Which ratio is equivalent to 10:85

Nata [24]

<span>First, find what are the numbers that can be divided to 10 and 85. The numbers 10 and 85 can be divided by 5. 10 divided by 5 is equals to 2 and 85 divided by 5 is equals to 17. Ratio is just like a fraction, you need to reduce its terms if you need to. Let’s say 10:85 is a fraction and since it is obvious that it can be divided by 5, you just need to reduce its term. 10/85 can be reduced into 2/17 which is just the same with ratios 10:85 is equals to 2:17.<span>
</span></span>

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4 years ago