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IrinaVladis [17]
3 years ago
15

Rewrite these in increasing order of length: 133 dm. 433 cm, 308 km, 91 mm

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0

\boxed{91mm

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m

Therefore, we can compute the following:

\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m

Writing this in increasing order:

0.091m

<h2>Learn more:</h2>

jovian planets in order of increasing distance from the Sun: brainly.com/question/12534549

#LearnWithBrainly

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A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
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Step-by-step explanation:

Information given:

X= 36 represent the families owned at least one DVD player

n= 85 represent the total number of families

\hat p=\frac{36}{85}= 0.424 represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

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3 years ago
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