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Alex777 [14]
3 years ago
10

While traveling to Europe, Phelan exchanged 250 US dollars for euros. He spent 150 euros on his trip. After returning to the Uni

ted States he converts his money back to US dollars. How much of the original 250 US dollars does Phelan now have?
Mathematics
1 answer:
marishachu [46]3 years ago
7 0
Hello!

He spends 150 euros so he has 32.66 euros at the end of his trip. To convert it back he does: 1.3687 dollars/1 euro • 32.66 euros = 44.701742 dollars = 44.70 dollars
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A researcher has developed a new drug designed to reduce blood pressure. In an experiment, 21 subjects were assigned randomly to
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Answer:

Step-by-step explanation:

Hello!

The objective of the research is to compare the newly designed drug to reduce blood pressure with the standard drug to test if the new one is more effective.

Two randomly selected groups of subjects where determined, one took the standard drug (1- Control) and the second one took the new drug (2-New)

1. Control

X₁: Reduction of the blood pressure of a subject that took the standard drug.

n₁= 23

X[bar]= 18.52

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2. New

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The parameter of study is the difference between the two population means (no order is specified, I'll use New-Standard) μ₂ - μ₁

Assuming both variables have a normal distribution, there are two options to estimate the difference between the two means using a 95% CI.

1) The population variances are unknown and equal:

[(X[bar]₂-X[bar]₁)±t_{n_1+n_2-2;1-\alpha /2}*(Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  })]

t_{n_1+n_2-2;1-\alpha /2}= t_{23+21-2;1-0.025}= t_{42;0.975}= 2.018

Sa=\sqrt{\frac{(n_1-1)*S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{22*7.15^2+20*8.01^2}{42} }= 7.57

[23.48-18.52]±2.018*(7.57*\sqrt{\frac{1}{21} +\frac{1}{23}  })]

[0.349; 9.571]

2) The population variables are unknown and different:

Welche's approximation:

[(X[bar]₂-X[bar]₁)±t_{Dfw;1-\alpha /2}*( \sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} })]

Df_{w}= \frac{(\frac{S_1^2}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S_1^2}{n_1} )^2}{n_1-1}+ \frac{(\frac{S_2^2}{n_2} )^2}{n_2-1}  } =  \frac{(\frac{7.15^2}{23} +\frac{8.01^2_2}{21} )^2}{\frac{(\frac{7.15^2}{21} )^2}{20}+ \frac{(\frac{8.01^2}{23} )^2}{22}  } = 42.85= 42

t_{Df_w;1-\alpha /2}= t_{42; 0.975}=  2.018

[(23.48-18.52)±2.018\sqrt{\frac{7.15^2}{23} +\frac{8.01^2}{21} }]

[0.324; 9.596]

I hope this helps!

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3 years ago
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Answer:

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Step-by-step explanation:

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Now what you do is you take the price of the time and multiply it by the .70

So 27.00 * .7 = 18.90

So Noah paid 18.90

5 0
3 years ago
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