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lora16 [44]
3 years ago
13

Please help please c::::::::::

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0
The answer would be C.III. If both the x and y are negative (less than 0), that would mean it is in the 3rd quadrant of a graph. 
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Integral rational trigonometric ​
abruzzese [7]

Substitute <em>x</em> = 3 - 2 cos(<em>θ</em>) and d<em>x</em> = 2 sin(<em>θ</em>) d<em>θ</em> (where "sin" = "sen"). So we have

∫ sin(<em>θ</em>) / (3 - 2 cos(<em>θ</em>)) d<em>θ</em> = 1/2 ∫ 1/<em>x</em> d<em>x</em>

= 1/2 ln|<em>x</em>| + <em>C</em>

= 1/2 ln(3 - 2 cos(<em>θ</em>)) + <em>C</em>

(We can remove the absolute value because -1 ≤ cos(<em>θ</em>) ≤ 1, so 1 ≤ 3 - 2 cos(<em>θ</em>) ≤ 5, and |<em>x</em>| = <em>x</em> when <em>x</em> ≥ 0.)

8 0
3 years ago
Lily sees 15 tan puppies and 8 white puppies at the pet store how many more tan puppies does she see
IgorLugansk [536]
She sees 7 more than puppies (15 - 8 = 7)
3 0
3 years ago
2. f(x) = 3(x - 2)2 + 6<br>a. Standard Form:​
Alexandra [31]

Answer:

{3x}^{2}   - 4x + 10 = 0

Step-by-step explanation:

3(x - 2) {}^{2}  + 6 \\  3 \times x {}^{2}  - 4x +  {2}^{2}  + 6 \\ 3x {}^{2} - 4x + 4 + 6 \\  {3x}^{2}   - 4x + 10 = 0

6 0
3 years ago
A- CE=CD <br> B- CE = CA <br> C- BF=DF <br> D- DF=EF<br><br> please help!!
Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that \overleftrightarrow{FG} and \overleftrightarrow{AB} are perpendicular.

The two statements if true that guarantee  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB} are;

  • \overline{CE} = \overline{CD}
  • \overline{DF} = \overline{EF}

Reasons:

The given diagram is the construction of the line \mathbf{\overleftrightarrow{FG}} perpendicular to line \mathbf{\overleftrightarrow{AB}}.

Required:

The two statements that guarantee that  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}.

Solution:

From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line \overleftrightarrow{AB}, therefore;

\overline{CE} = \mathbf{\overline{CD}} arcs drawn from the same radius.

\overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}, given.

Therefore;

\overline{DF} = \overline{EF}  by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

7 0
3 years ago
A robot that makes _/8 of a boat per day will make 7 boats in 8 days
Sidana [21]
7/8 boats per day will make it
8 0
3 years ago
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