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2 years ago

Layla has 3/4 of a can of paint. She uses 2/3 of the paint for one wall in her bedroom. How much of the can did she use?

Mathematics

2 answers:

Scorpion4ik [409]2 years ago

8 0

Answer:

5/12

Step-by-step explanation:

Mark him brain

ki77a [65]2 years ago

4 0

Answer:

17/12 or 1 and 5/12.

Step-by-step explanation:

3/4 and 2/3 needs to have the same denomenator. So, what number does both 4 and 3 go into? 12. So, 4x3=12, so we multiply the numerator by 3 too, to get 9 --> 9/12. Then, we see that 4x3=12 for 3 too so we multiply 2 by 4 which gets us 8 --> 8/12. So, now we add 9/12 + 8/12 to get 17/12, which then we make into a mixed number to get 1 and 5/12.

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I need help on this, please!

xenn [34]

Answer:

(5,9) and (5,3)

Step-by-step explanation:

Because the point is (5,6), and the question tells you to plot two points that are three units away from (5,6) but share the same X coordinate.

The X coordinate is 5. And 6 is the Y coordinate, if we do 6-3=2. 6+3=9.

4 0

3 years ago

Question 1 options:

OLEGan [10]

Answer:

4000 $m^{3}$

Step-by-step explanation:

V = 1/3(Bh) where B is the area of the base and h is the height of the pyramid

B = 20(20) = 400 h = 30

V = 1/3(400)(30) = 4000 $m^{3}$

5 0

2 years ago

What forms of the following equation in?<br><br> y=5x−3

alexdok [17]

5x-y=3
Not sure if it’s correct

4 0

2 years ago

Read 2 more answers

Convert,the complex number into polar form: 4+4i

kow [346]

Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
r = 4√(2)
r = 4(1.414)
r = 5.656

$cos\theta = \frac{a}{r}$
$cos\theta = \frac{4}{4\sqrt{2}}$
$cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$cos\theta = \frac{4\sqrt{2}}{4(2)}$
$cos\theta = \frac{4\sqrt{2}}{8}$
$cos\theta = \frac{\sqrt{2}}{2}$
$2(cos\theta) = 2(\frac{\sqrt{2}}{2})$
$2cos\theta = \sqrt{2}$
$2cos\theta = 1.414$

$sin\theta = \frac{b}{r}$
$sin\theta = \frac{4}{4\sqrt{2}}$
$sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$sin\theta = \frac{4\sqrt{2}}{4(2)}$
$sin\theta = \frac{4\sqrt{2}}{8}$
$sin\theta = \frac{\sqrt{2}}{2}$
$2(sin\theta) = 2(\frac{\sqrt{2}}{2})$
$2sin\theta = \sqrt{2}$
$2sin\theta = 1.414$

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

$\theta = tan^{-1}\frac{b}{a}$
$\theta = tan^{-1}\frac{4}{4}$
$\theta = tan^{-1}(1)$
$\theta = 45$

The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).

5 0

3 years ago

The vertices of a square are A(–2, 4), B(4, 4), C(4, –2), and D(–2, –2). The diagonals of the square intersect at their midpoint

sertanlavr [38]

A(–2, 4), B(4, 4), C(4, –2), D(–2, –2)
-> select some diagonal: AC
midpoint is at A+(1/2)*AC

-> calculate vector AC:
AC=(4-(-2),-2-4)=(6,-6)
-> calculate half length of AC:
(1/2)*AC=(3,-3)

A+(1/2)*AC=
(-2,4)+(3,-3)=(1,1) which is the midpoint

so the first option is correct

4 0

2 years ago