Please explain in depth

Click on the picture thanks so much

-BARSIC- [3]

Answer:

$3.06

Step-by-step explanation:

First we need to calculate the mark up

The mark-up rate is 150% = 1.5 as a decimal

New price = original price + original price * markup rate

= 61.20 + 61.20* 1.50

= 61.20 + 91.80

= 153

The new price is 153.00

Commission is the price times his commission rate

commission = price* .02

= 153*.02

= 3.06

Neil will make 3.06 on the sale of the table

7 0

3 years ago

A company sells its printers to customers in order to make a profit of 25% calculate the price the company paid for a printer wh

ioda

The company paid $2000 for the printer

Step-by-step explanation:

Let x be the price of the printer for which the company bought it.

If x is the price of printer, then 25% of x will be the profit made by the company.

That is:

0.25x

According to the statement,

The cost and profit earned by company are equal to 2500

So,

$x+0.25x = 2500\\1.25x = 2500$

Dividing both sides by 1.25

$\frac{1.25x}{1.25} = \frac{2500}{1.25}\\x = 2000$

Hence,

The company paid $2000 for the printer

Keywords: Percentage, Profit

Learn more about percentage at:

#LearnwithBrainly

7 0

3 years ago

You want path 1 to be a continuous distance of 1.5 km from the center of the habitat 1) path one represents what mathematical ob

oksian1 [2.3K]

If we consider the center of the habitat to be a point - then a circle with a radius of 1.5 km <u /><u />would satisfy the problem.

The path would go around the point (habitiat) and would always be 1.5 km from that point.

3 0

3 years ago

Read 2 more answers

Thanks!! got a 100% on the test bc of brain.ly

Lorico [155]

Your welcome ig brainly helps everyone in need of help

5 0

3 years ago

Read 2 more answers

Sarah claims that the thickness of the spearmint gum she produces is 7.5 one-hundredths of an inch. A quality control specialist

satela [25.4K]

Answer:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

$p_v =2*P(t_{(9)}>1.539)=0.158$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

Step-by-step explanation:

Data given and notation

Data: 7.65, 7.60, 7.65, 7.7, 7.55, 7.55, 7.4, 7.4, 7.5, 7.5

We can begin calculating the sample mean given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And the sample deviation given by:

$s=\sart{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And we got:

$\bar X=7.55$ represent the sample mean

$s=0.103$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =7.5$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 7.5 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 7.5$

Alternative hypothesis: $\mu \neq 7.5$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.55-7.5}{\frac{0.103}{\sqrt{10}}}=1.539$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=10-1=9$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(9)}>1.539)=0.158$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis.

3 0

3 years ago

Please explain in depth​

Please explain in depth