The two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.
<h3>What is a quadratic equation?</h3>
A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.
The standard form of the quadratic equation is,

Here, (<em>a,b,c</em>) are the real numbers and <em>x </em>is the variable.
To find the value of x, the following formula is used,

The given equation is,

To solve this equation, we need to apply some mathematical operations over it. Let's start with opening the brackets.

On comparing with standard equation we get,

Put this values in the above formula,

Hence, the two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.
Learn more about the quadratic equation here;
brainly.com/question/1214333