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Montano1993 [528]
2 years ago
14

Proof true or false: For all integers a,b,and c,if ab|c then a|c and b|c

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
4 0

Answer with explanation:

It is given that for three integers , a, b and c, if

              \frac{ab}{c}\rightarrow then, \frac{a}{c} \text{or} \frac{b}{c}

Since , a b is divisible by c , following are the possibilities

1.→ a and b are prime integers .Then , c will be prime number either equal to a or b.

2.→a and b are not prime integers ,then any of the factors of a or b will be equal to c.For example:

 ⇒a=m × n

 b=p × q× c

or,

⇒a=u×v×c

b=s×t

So, whatever the integral values taken by a, and b, if \frac{ab}{c} then either of  \frac{a}{c} \text{or} \frac{b}{c} is true.

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Answer:

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  • x-intercepts: (-3, 0), (-1, 0), (1, 0)

Step-by-step explanation:

We notice the first pair of coefficients is the same as the last pair (with the sign changed). This means we can factor by grouping.

  f(x) = (2x^3 +6x^2) -(2x +6)

  f(x) = 2x^2(x +3) -2(x +3)

  f(x) = 2(x^2 -1)(x +3) = 2(x -1)(x +1)(x +3)

The factors are made to be zero when x is 1, -1, or -3.

The x-intercepts are (1, 0), (-1, 0), (-3, 0).

The y-intercept is the constant, -6.

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Answer:

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angles = 30°, 72°, 78°

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Jayson’s car can go 300 miles on 12.5 gallons of gasoline. How far can he drive on 42 gallons of gas?
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