Aaron kicked a soccer ball with an initial velocity of 39 feet per

you had a party at your house. after the party, you had 0.5 of a liter of soda remaining. how many milliliters of soda did you h

photoshop1234 [79]

A liter is 1000 mL so half of 1000 = 500

500 mL is the answer!

6 0

3 years ago

-5(3)(2)=? show how you got the answer

qwelly [4]

Answer:

-30

Step-by-step explanation:

i multiplied 2 times 3 gave my 6 multiplied by negative 5 so the answer stays negative

the answer is - 30

5 0

3 years ago

Read 2 more answers

The length of a rectangle is four more than three times its width. the area of the rectangle is 25. write an algebraic model for

Dafna11 [192]

width (w) = w

Length (L) = 3w + 4

Area (A) = L x w

25 = (3w + 4)w

25 = 3w² + 4w

0 = 3w² + 4w - 25

w = $\frac{-2 +/-\sqrt{79} }{3}$

w ≈ 2.3, w ≈ -3.6 (width cannot be negative!)

w ≈ 2.3

Length (L) = 3w + 4 = 3(2.3) + 4 = 6.9 + 4 = 10.9

Answer: width=2.3, Length=10.9

4 0

3 years ago

Applying One-Step Inequalities

sergij07 [2.7K]

Answer:

1). n </=6

2). n > 27.25

3). n > 10.50

8 0

3 years ago

Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!

blagie [28]

Question 4

1) $\overline{BD}$ bisects $\angle ABC$ , $\overline{EF} \perp \overline{AB}$ , and $\overline{EG} \perp \overline{BC}$ (given)

2) $\angle FBE \cong \angle GBE$ (an angle bisector splits an angle into two congruent parts)

3) $\angle BFE$ and $\angle BGE$ are right angles (perpendicular lines form right angles)

4) $\triangle BFE$ and $\triangle BGE$ are right triangles (a triangle with a right angle is a right triangle)

5) $\overline{BE} \cong \overline{BE}$ (reflexive property)

6) $\triangle BFE \cong \triangle BGE$ (HA)

Question 5

1) $\angle AXO$ and $\angle BYO$ are right angles, $\angle A \cong \angle B$ , $O$ is the midpoint of $\overline{AB}$ (given)

2) $\triangle AXO$ and $\triangle BYO$ are right triangles (a triangle with a right angle is a right triangle)

3) $\overline{AO} \cong \overline{OB}$ (a midpoint splits a segment into two congruent parts)

4) $\triangle AXO \cong \triangle BYO$ (HA)

5) $\overline{OX} \cong \overline{OY}$ (CPCTC)

Question 6

1) $\angle B$ and $\angle D$ are right angles, $\overline{AC}$ bisects $\angle BAD$ (given)

2) $\overline{AC} \cong \overline{AC}$ (reflexive property)

3) $\angle BAC \cong \angle CAD$ (an angle bisector splits an angle into two congruent parts)

4) $\triangle BAC$ and $\triangle CAD$ are right triangles (a triangle with a right angle is a right triangle)

5) $\triangle BAC \cong \triangle DCA$ (HA)

6) $\angle BCA \cong \angle DCA$ (CPCTC)

7) $\overline{CA}$ bisects $\angle ACD$ (if a segment splits an angle into two congruent parts, it is an angle bisector)

Question 7

1) $\angle B$ and $\angle C$ are right angles, $\angle 4 \cong \angle 1$ (given)

2) $\triangle BAD$ and $\triangle CAD$ are right triangles (definition of a right triangle)

3) $\angle 1 \cong \angle 3$ (vertical angles are congruent)

4) $\angle 4 \cong \angle 3$ (transitive property of congruence)

5) $\overline{AD} \cong \overline{AD}$ (reflexive property)

6) $\therefore \triangle BAD \cong \triangle CAD$ (HA theorem)

7) $\angle BDA \cong \angle CDA$ (CPCTC)

8) $\therefore \vec{DA}$ bisects $\angle BDC$ (definition of bisector of an angle)

8 0

1 year ago