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3 years ago

The cost of a sweatshirt was on sale for $18. Find the

Mathematics

2 answers:

Zolol [24]3 years ago

5 0

page : http://bit.ll

Shalnov [3]3 years ago

4 0

25-18=7

7/25(100)=28

It was decreased by 28%.

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I’m not sure why the picture didn’t work

lutik1710 [3]

Answer:

4.1

Step-by-step explanation:

6 0

2 years ago

A bag of gumballs contains 2 pink, 3 orange, 4 blue, 2 red, and 1 yellow

podryga [215]

Answer:

1/4

Step-by-step explanation:

there are 12 gumballs in total

1 yellow + 2 pink = 3 gumballs out of all 12

3 /12 is simplified to 1/4 as both numbers is divisible by 3

8 0

2 years ago

Expression of "Eight less than half the sum of 4 and k” into symbol

jolli1 [7]

Answer:

$\frac{4+k}{2} -8$

Step-by-step explanation:

We're going to have to work backwards.

The sum of 4 and k is $4+k$ .

Half is simply that divided by 2.

$\frac{4+k}{2}$

Now, we'll subtract 8 from it.

$\frac{4+k}{2} -8$

Bam!

7 0

2 years ago

Help! Will give branliest!!

sergey [27]

Hello from MrBillDoesMath!

Answer:

sin(A) = k/c

sin(C) = k/a

Discussion:

By definition of sine ,

sin(A) = side opposite angle / hypotenuse = k/c

sin(C) = side opposite angle/ hypotenuse = k/a

Added remark:

From the first equation, k = c sin(A). From the second equation k = asin(C). Hence.

asin(C) = csin(A) => divide both sides by "ac"

sin(C)/ c = sin(A)/a

Which is the law of sines for a triangle.

Thank you,

MrB

4 0

2 years ago

Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]

Anastaziya [24]

Answer:

$f_{avg}=e-1$

Step-by-step explanation:

We are given that a function

$f(x)=e^{\frac{x}{7}}$

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx$

$f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}$

By using the formula

$\int e^{ax}=\frac{e^{ax}}{a}$

$f_{avg}=(e-e^0)=e-1$

Because $e^0=1$

$f_{avg}=e-1$

Hence, the average value of function on interval [0,7]

$f_{avg}=e-1$

8 0

3 years ago