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IrinaK [193]
3 years ago
13

Suppose that we examine the relationship between high school GPA and college GPA. We collect data from students at a local colle

ge and find that there is a strong, positive, linear association between the variables. The linear regression predicted college GPA = 1.07 + 0.62 * high school GPA. The standard error of the regression, se, was 0.374. What does this value of the standard error of the regression tell us?
Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

The typical error between a predicted college GPA using this regression model and an actual college GPA for a given student will be about 0.374 grade points in size (absolute value).

Step-by-step explanation:

The linear regression line for College GPA based on High school GPA is:

<em>College GPA</em> = 1.07 + 0.62 <em>High-school GPA</em>

It is provided that the standard error of the regression line is,

s_{e}=0.374

The standard error of a regression line is the average distance between the predicted value and the regression equation.

It is the square root of the average squared deviations.

It is also known as the standard error of estimate.

The standard error of 0.374 implies that:

The typical error between a predicted college GPA using this regression model and an actual college GPA for a given student will be about 0.374 grade points in size (absolute value).

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Please help thanks!
babunello [35]

Answer:

10 to 15

Step-by-step explanation:

the spread is the start and stop of points data. It goes from the least point to the most point, here there is a dot (two technally) on 10 and a dot on 15 where the data stops so the data spread is 10-15

7 0
3 years ago
The perimeter of a rectangle is found by using the formula P = 2l + 2w, where P is the perimeter, l is the length and w is the w
velikii [3]

Answer:

#1: 11 cm

#2: 16.5 in

#3: 2.5 feet

Step-by-step explanation:

#1

P=2l+2w Solve for width by substracting 2l on both sides to isolate 2w

P-2l=2w

or

2w=P-2l

Replace.

2w=26-2(2)\\2w=26-4\\2w=22\\w=\frac{22}{2}\\ w=11cm

----------------------------------------------------------------------------

#2

P=2l+2w

P=2(3.5)+2(4.75)\\P =7+9.5\\P=16.5in

----------------------------------------------------------------------------

#3

P=2l+2w

Solve for l

2l=P-2w\\2l=7-2(1)\\2l=7-2\\2l=5\\l=\frac{5}{2}\\ l=2.5feet

5 0
3 years ago
The graph of y=f(x) is above. If f(−4)=k, what is the value of f(k)?
cupoosta [38]

Answer:

B

The answer is B, which is -1.5.

3 0
3 years ago
The shape of the distribution of the time required to get an oil change at a 15-minute oil-change facility is unknown. However,
kolezko [41]

Answer:

(a) 0.0128 to 4 decimal places

(b) The 90% confidence interval is 119.1 < μ < 121.0 to 1 decimal places

Step-by-step explanation:

See the attached documents and graphs. Cheers!

Download pdf
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> pdf </span>
4de97e6d942fe2c9047a396b82fccba0.png
0b940014a3beda8e854506c0084127b3.png
8 0
3 years ago
PLEASE HELP ASAP!!!
barxatty [35]

Answers:

  • <u>24000 dollars</u> invested at 4%
  • <u>18000 dollars</u> was invested at 7%

======================================================

Work Shown:

x = amount invested at 4%

If she invests x dollars at 4%, then the rest (42000-x) must be invested at the other rate of 7%

She earns 0.04x dollars from that first account and 0.07(42000-x) dollars from the second account

This means we have

0.04x+0.07(42000-x)

0.04x+0.07*42000-0.07x

0.04x+2940-0.07x

-0.03x+2940

This represents the total amount of money earned after 1 year.

We're told the amount earned in interest is $2220, so we can say,

-0.03x+2940 = 2220

-0.03x = 2220-2940

-0.03x = -720

x = -720/(-0.03)

x = 24000 dollars is the amount invested at 4%

42000-x = 42000-24000 = 18000 dollars was invested at 7%

----------------------

As a check, we can see that

18000+24000 = 42000

and also

0.04x = 0.04*24000 = 960 earned from the first account

0.07*18000 = 1260 earned from the second account

1260+960 = 2220 is the total interest earned from both accounts combined

This confirms our answers.

7 0
3 years ago
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