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3 years ago

Factor the quadratic expression 3xsquared+4x-4

Mathematics

1 answer:

Schach [20]3 years ago

5 0

Answer:

(3x − 2) (x + 2)

Step-by-step explanation:

For a quadratic ax² + bx + c, you can factor using the AC method.

1. First, multiply a and c.

2. Next, find factors of ac that add up to b.

3. Divide the factors by a. Reduce if possible.

4. The numerator of the fraction becomes the constant. The denominator of the fraction becomes the coefficient.

3x² + 4x − 4

In this case, a = 3, b = 4, and c = -4.

1. 3 × -4 = -12

2. Factors of -12 that add up to 4 are -2 and +6

3. Divide by 3 and reduce: -2/3, 6/3 = 2/1

4. The factors are 3x − 2 and x + 2

3x² + 4x − 4 = (3x − 2) (x + 2)

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2x+y=3 passes from origin. is this statement true or false

WINSTONCH [101]

Answer:

the answer is false.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Plss help i beg you!

frosja888 [35]

Answer:

Step-by-step explanation:

<u>Given expression:</u>

3(x + y) +2x² + (1 + y)²

<u>Find its value when x = 4 and y = 1, substitute:</u>

3(4 + 1) + 2*4² + (1 + 1)² =
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7 0

3 years ago

Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in

Luda [366]

ANSWER: 32 five-dollar bills

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EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

$\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.$

Divide both sides of equation (II) by 5 so our numbers become smaller

$\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.$

Rearrange (I) to solve for y so that we can substitute into (II)

$\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}$

Substituting this into equation (II) for the y:

$\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}$

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

$y = 38 - 32 = 6$

32 five-dollar bills and 6 ten-dollar bills

7 0

3 years ago

The midpoint of the segment as an ordered pair (-4,8) (-4,2)

tiny-mole [99]

Answer:

Step-by-step explanation:

(-4,8) & ( -4,2)

$Midpoint=\left(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2} \right)\\\\\\=\left(\dfrac{-4-4}{2},\dfrac{8+2}{2}\right)\\\\\\=\left(\dfrac{-8}{2},\dfrac{10}{2} \right)$