3 years ago

Solve for x. y=4+bx^2

Mathematics

1 answer:

kicyunya [14]3 years ago

3 0

$y=4+bx^2$

$bx^2 = y - 4$

$x^2 = \dfrac{y-4}{b}$

$x = \pm \sqrt{ \dfrac{y-4}{b} }$

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