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uranmaximum [27]
4 years ago
5

Which feature of a human community is similar to a niche in a biological community?

Physics
1 answer:
pogonyaev4 years ago
7 0

Answer: C. occupation

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56.321, 56.32, 56.2 is the answer
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The light reactions could be viewed as analogous to a hydro-electric dam. In that case, the wall of the dam that holds back the
Viktor [21]

The light reactions could be viewed as analogous to a hydroelectric dam. In that case, the wall of the dam that holds back the water would be analogous to the thylakoid membrane.

Thylakoid membrane is present in cyanobacteria and chloroplasts of plants. It plays a crucial role in photosynthesis and photosystem II reactions.

In general, these are the regions where light-dependent reactions take place. The thylakoid membrane is a lipid-bound membrane that maintains potential difference and also controls the flow of liquids across the membrane during light reactions.

In the provided case, we can see that the wall of the dam holds back the water, similarly, in light-dependent reactions, thylakoid membranes control the liquid flow and also regulate the potential gradient across the membrane and also allow the selective proteins to pass through.

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3 0
2 years ago
An electric motor can drive grinding wheel at two different speeds. When set to high the angular speed is 2000 rpm. The wheel tu
shutvik [7]

a) The initial angular speed is 209.3 m/s

b) The angular acceleration is -1.74 rad/s^2

c) The angular speed after 40 s is 139.7 rad/s

d) The wheel makes 1501 revolutions

Explanation:

a)

The initial angular speed of the wheel is

\omega_i = 2000 rpm

which means 2000 revolutions per minute.

We have to convert it into rad/s. Keeping in mind that:

1 rev = 2\pi rad

1 min = 60 s

We find:

\omega_i = 2000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=209.3 rad/s

b)

To find the angular acceleration, we have to convert the final angular speed also from rev/min to rad/s.

Using the same procedure used in part a),

\omega_f = 1000 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=104.7 rad/s

Now we can find the angular acceleration, given by

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_i = 209.3 rad/s is the initial angular speed

\omega_f = 104.7 rad/s is the final angular speed

t = 60 s is the time interval

Substituting,

\alpha = \frac{104.7-209.3}{60}=-1.74  rad/s^2

c)

To find the angular speed 40 seconds after the initial moment, we use the equivalent of the suvat equations for circular motion:

\omega' = \omega_i + \alpha t

where we have

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 40 s, we find

\omega' = 209.3 + (-1.74)(40)=139.7 rad/s

d)

The angular displacement of the wheel in a certain time interval t is given by

\theta=\omega_i t + \frac{1}{2}\alpha t^2

where

\omega_i = 209.3 rad/s

\alpha = -1.74 rad/s^2

And substituting t = 60 s, we find:

\theta=(209.3)(60) + \frac{1}{2}(-1.74)(60)^2=9426 rad

So, the wheel turns 9426 radians in the 60 seconds of slowing down. Converting this value into revolutions,

\theta = \frac{9426 rad}{2\pi rad/rev}=1501 rev

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8 0
3 years ago
Two blocks, joined by a string, have masses of 6.0 kg and 9.0 kg. They rest on a frictionless horizontal surface. A 2nd string,
Gennadij [26K]

Answer:

Explanation:

30 N force is pulling total mass of 15 kg , so acceleration in the system of masses

= 30 / 15

= 2 m / s²

Let us now consider forces acting on 9 kg . 30 N is pulling it in forward direction . Tension T in the string attached to it is pulling it in reverse direction

so net force on it

30 - T

Applying Newton's law of motion on it

30 - T = mass x acceleration

30 - T = 9  x 2

30 - 18 = T

T = 12 N

4 0
4 years ago
How much does force increase if mass is doubled
katrin2010 [14]
First of all, the question is worded somewhat ambiguously because mass does not necessarily imply that there is a force (i.e. an object could be stationary in a system with no gravity and not have a force, or something of the like). Moreover, simply because an object is twice the mass does not mean the force will change. 

However, we know from Newton's second law that F = ma. Therefore, force will increase or decrease proportionally with mass. This means if an object maintains a contestant acceleration and its mass doubles, the force that it provides will also double. 
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