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qaws [65]
3 years ago
15

According to Bernoulli's fluid formula a An increase in the speed will lower the internal pressure b An increase in the speed wi

ll increase the internal pressure c The internal pressure doesn't change with the speed
Physics
1 answer:
lorasvet [3.4K]3 years ago
5 0

Answer:

a An increase in the speed will lower the internal pressure

Explanation:

Bernoulli's fluid formula

P_1+\frac{1}{2}\rho v_1^2+\rho gh_1=P_1+\frac{1}{2}\rho v_2^2+\rho gh_2

where

P = Pressure

ρ = Density of fluid

g = Acceleration due to gravity

h = Height

v = Velocity of fluid

If there is no change in height then we get

P_1+\frac{1}{2}\rho v_1^2=P_1+\frac{1}{2}\rho v_2^2\\\Rightarrow P+\frac{1}{2}\rho v^2=constant

According to the Bernoulli's principle when the speed of the fluid is larger in a region of streamline flow the pressure is smaller in that region. From the above equation it can be seen that increase in speed should simultaneously reduce pressure in order for their sum to be constant.

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Astronauts are trained for take-off in a high-speed centrifuge of 4.7 m radius that spins in the horizontal plane.
Leokris [45]

Answer:

a) 1.94 \frac{rad}{s}

b) 9.12\frac{m}{s}

c) Towards the center of the centrifuge

Explanation:

a)

Becuse the centrifuge rotates in circular motion, there's an angular acceleration tha simulates high gravity accelerations

a_{rad}=\omega r^{2}

with r the radius and ω the amgular velocity, in or case a_rad=3.5g so:

3.5g=\omega r^{2} and g=9.8\frac{m}{s^{2}}

solving for ω:

\omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}

\omega = 1.94 \frac{rad}{s}

b) Linear speed (v) and angular speed are related by:

v=\omega r =(1.94)(4.7)

v= 9.12\frac{m}{s}

c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.

8 0
3 years ago
the chef was careless and put the aluminum cookie sheet directly on the hot stove, which melted 0.05 kg of the aluminum. how muc
sergejj [24]

Heat required to melt 0.05 kg of aluminum is 28.7 kJ.

<h3>What is the energy required to melt 0.05 kg of aluminum?</h3>

The heat energy required to melt 0.05 kg of aluminum is obtained from the heat capacity of aluminum and the melting point of aluminum.

The formula to be used is given below:

  • Heat required = mass * heat capacity * temperature change

Assuming the aluminum sheet was at room temperature initially.;

Room temperature = 25 °C

Melting point of aluminum = 660.3 °C

Temperature difference = (660.3 - 25) = 635.3 903

Heat capacity of aluminum = 903 J/kg/903

Heat required = 0.05 * 903 * 635.3

Heat required = 28.7 kJ

In conclusion, the heat required is obtained from the heat change aluminum and the mass of the aluminum melted.

Learn more about heat capacity at: brainly.com/question/21406849

#SPJ1

3 0
2 years ago
a 10kg cement block horizontally at 6 m/s plows into a bank of sand and comes to a stop in 2.0 m/s. What is the average impact f
Gnesinka [82]
I assume the block plows into the bank of sand with a velocity of 6 m/s and comes to a stop in 2 s.

\bar Ft =  \Delta mv  \\  \\  \bar F =  \frac{\Delta mv }{t}  \\  \\  \bar F \ avarage \ Force \\  m \ momentum \\ v \ velocity \\ t \ time
7 0
3 years ago
A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir
vovikov84 [41]
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,

   KE1  = KE2

The kinetic energy of the system before the collision is solved below.

  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²

This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
6 0
3 years ago
Martin has severe myopia, with a far point on only 17 cm. He wants to get glasses that he'll wear while using his computer whose
marusya05 [52]

Answer:

Explanation:

Far point = 17 cm . That means he can not see beyond this distance .

He wants to see at an object at 65 cm away . That means object placed at 65 has image at 17 cm by concave lens . Using lens formula

1 / v - 1 / u = 1 / f

1 / - 17 - 1 / - 65 = 1 / f

= 1 / 65 - 1 / 17

= -  .0434 = 1 / f

power = - 100 / f

= - 100 x .0434

= - 4.34 D .

6 0
4 years ago
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