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vo = 25 m/sec
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
The amount of extra electrons present on the negative surface is
57.2 x
.
Distance =1.6 cm
Side = 24 cm
Electric field = 18000 N/C
Calculating the capacitance in the metal plates is necessary.
Using the capacitance formula

Putting the value
C = 8.85 x
x (24 x 
/1.6 x 
C = 0.318 x
F
<h3>Calculation of potential</h3>
V = Ed
V = 18000 x 1.6 x
V
V = 288 V
<h3>Calculation of charge</h3>
Q = CV
Q = 0.318 x
x 288
Q = 91.54 x
C
Charge on the both the plates
Q = +91.54 x 
Q = - 91.54 x 
Calculation of excess electrons on the negative surface:
n = q/e
n = 91.54 x
/ 1.6 x 
n = 57.2 x
electrons
Hence, the number of excess electrons on the negative surface is
57.2 x
.
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Answer:
Stars are forming in the spiral arms so there are high mass, hot, blue stars in the arms.
Explanation:
Answer:
0.08kg
Explanation:
K.E = 1/2 mv^2
v = 970m/s
K.E = 3.9x 10^3J= 3900J
K.E = 1/2 mv^2
3900 = 1/2 m x 970x 970
3900 = 1/2 ×940900m
3900 = 470450m
m = 3900/470450 = 0.00828993516 = 0.008kg
It must be the same force, because when it is applied, it is 'distributed' equally in each of the points (either a tendon or a wire or a rope or something similar). The 128N resistance should be preserved for tendons that have the same diameter.
Therefore the correct answer is A.