Ask question

Ask question

All categories

3 years ago

11

In a carnival booth, you can win a stuffed giraffe if you toss a quarter into a small dish. the dish is on a shelf above the poi

nt where the quarter leaves your hand and is a horizontal distance of 2.1 m from this point. if you toss the coin with a velocity of 6.4 m>s at an angle of 60° above

1 answer:

Georgia [21]3 years ago

3 0

components of the speed of the coin is given as

$v_x = v cos60$

$v_x = 6.4 cos60 = 3.2 m/s$

$v_y = vsin60$

$v_y = 6.4 sin60 = 5.54 m/s$

now the time taken by the coin to reach the plate is given by

$t = \frac{\delta x}{v_x}$

$t = \frac{2.1}{3.2}$

$t = 0.656 s$

now in order to find the height

$h = vy * t + \frac{1}{2} at^2$

$h = 5.54 * 0.656 - \frac{1}{2}*9.8*(0.656)^2$

$h = 1.52 m$

so it is placed at 1.52 m height

You might be interested in

You raise a bucket of water from the bottom of a well that is 12 m deep. the mass of the bucket and the water is 5.00 kg, and it

MArishka [77]

Given: Mass m = 5.00 Kg; Height h = 12 m; Time t = 15 s

Required: Power P = ?

Formula: P = Fd/t = mgh/t

P = (5.0 Kg)(9.8 m/s²)(12 m)/15 s

P = 39.2 Kg.m²/s² or

P = 39.2 J

4 0

3 years ago

What is physics? Why is it important in our life

-Dominant- [34]

Answer:

It helps us to know or be aware of some things that happen regular and teaches us about laws that guide us

8 0

4 years ago

Read 2 more answers

A uniform line charge of density λ lies on the x axis between x = 0 and x = L. Its total charge is 7 nC. The electric field at x

DedPeter [7]

Answer:

The electric field at x = 3L is 166.67 N/C

Solution:

As per the question:

The uniform line charge density on the x-axis for x, 0< x< L is $\lambda$

Total charge, Q = 7 nC = $7\times 10^{- 9} C$

At x = 2L,

Electric field, $\vec{E_{2L}} = 500N/C$

Coulomb constant, K = $8.99\times 10^{9} N.m^{2}/C^{2}$

Now, we know that:

$\vec{E} = K\frac{Q}{x^{2}}$

Also the line charge density:

$\lambda = \frac{Q}{L}$

Thus

Q = $\lambda L$

Now, for small element:

$d\vec{E} = K\frac{dq}{x^{2}}$

$d\vec{E} = K\frac{\lambda }{x^{2}}dx$

Integrating both the sides from x = L to x = 2L

$\int_{0}^{E}d\vec{E_{2L}} = K\lambda \int_{L}^{2L}\frac{1}{x^{2}}dx$

$\vec{E_{2L}} = K\lambda[\frac{- 1}{x}]_{L}^{2L}] = K\frac{Q}{L}[frac{1}{2L}]$

$\vec{E_{2L}} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{2L}] = \frac{63}{L^{2}}$

Similarly,

For the field in between the range 2L< x < 3L:

$\int_{0}^{E}d\vec{E} = K\lambda \int_{2L}^{3L}\frac{1}{x^{2}}dx$

$\vec{E} = K\lambda[\frac{- 1}{x}]_{2L}^{3L}] = K\frac{Q}{L}[frac{1}{6L}]$

$\vec{E} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{6L}] = \frac{63}{6L^{2}}$

Now,

If at x = 2L,

$\vec{E_{2L}} = 500 N/C$

Then at x = 3L:

$\frac{\vec{E_{2L}}}{3} = \frac{500}{3} = 166.67 N/C$

4 0

4 years ago

*Look at attachment for photo of object**

prohojiy [21]

A. The magnitude of the spring force (in N) acting upon the object is 15.9 N

B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²

C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).

<h3>A. How to determine the force </h3>

Extension (e) = 0.150 m
Spring constant (K) = 106 N/m
Force (F) = ?

F = Ke

F = 106 × 0.15

F = 15.9 N

<h3>B. How to determine the acceleration</h3>

Mass (m) = 0.52 Kg
Force (F) = 15. 9 N
Acceleration (a) =?

F = ma

Divide both sides by m

a = F / m

a = 15.9 / 0.52

a = 30.58 m/s²

<h3>C. How to determine the direction of the acceleration vector</h3>

Considering the diagram, we can see that the spring was pulled away from the equilibrium point.

Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.

Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

3 0

2 years ago

What sort of trade-offs do you think engineers make between functionality, safety, and aesthetics when building a real bridge?

skelet666 [1.2K]

They make sure the bridge is functional and safe before the add the
<span>aesthetics</span>

5 0

3 years ago

Read 2 more answers