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True [87]
2 years ago
10

The light reactions could be viewed as analogous to a hydro-electric dam. In that case, the wall of the dam that holds back the

water would be analogous to?.
Physics
1 answer:
Viktor [21]2 years ago
3 0

The light reactions could be viewed as analogous to a hydroelectric dam. In that case, the wall of the dam that holds back the water would be analogous to the thylakoid membrane.

Thylakoid membrane is present in cyanobacteria and chloroplasts of plants. It plays a crucial role in photosynthesis and photosystem II reactions.

In general, these are the regions where light-dependent reactions take place. The thylakoid membrane is a lipid-bound membrane that maintains potential difference and also controls the flow of liquids across the membrane during light reactions.

In the provided case, we can see that the wall of the dam holds back the water, similarly, in light-dependent reactions, thylakoid membranes control the liquid flow and also regulate the potential gradient across the membrane and also allow the selective proteins to pass through.

If you need to learn more about light reactions click here:

brainly.com/question/26623807

#SPJ4

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ehidna [41]
B) force & acceleration
6 0
3 years ago
A small first-aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s. After 2.5 s, what is the velocity of t
Artyom0805 [142]

Answer:

D = 30.625 m

Explanation:

given,

Speed of the climber = 1.3 m/s

time = 2.5 s

acceleration due to gravity = 9.8 m/s²

initial speed of the kit = 1.3 m/s

velocity of the kit after 2.5 s

using equation of motion

v = u + a t

v = 1.3 + 9.8 x 2.5

v = 25.8 m/s

distance travel by the kit in 2.5 s

v² = u² + 2 g h

25.8² = 1.3² + 2 x 9.8 x h

19.6 h = 663.95

h = 33.875 m

distance travel by the rock climber in 2.5 s

distance = speed of climber x time

h' = 1.3 x 2.5

h' = 3.25 m

Distance between kit and rock climber

D = h - h'

D = 33.875 - 3.25

D = 30.625 m

The kit is 30.625 m below climber.

8 0
3 years ago
A high diver of mass 74.0 kg jumps off a board 9.00 m above the water. If his downward motion is stopped 2.50 seconds after he e
stiv31 [10]

Answer:

1120 N

Explanation:

The velocity with which he hits the water can be found with kinematics:

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-9.00 m)

v = -13.3 m/s

Or it can be found with conservation of energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × -9.8 m/s² × -9.00 m)

v = -13.3 m/s

Sum of forces on the diver after he hits the water:

∑F = ma

F − mg = m Δv/Δt

F − (74.0 kg) (9.8 m/s²) = (74.0 kg) (0 m/s − (-13.3 m/s)) / (2.50 s)

F = 1120 N

6 0
3 years ago
What mathematical formula correctly expresses the relationship between force, mass and acceleration? A. m = F + a B. F = m / a C
IRINA_888 [86]

D. F=ma

F is for force, and that equals two things, M for mass and A for acceleration. When mass is accelerated, it gives you force. Force equals multiplying mass and its acceleration.

3 0
3 years ago
calculate the pressure produced by applying 15 n force on a flat surface having a width of 60 cm and a length of 5m
iren [92.7K]

Answer:

5 Pascals

Explanation:

Pressure is equal to force/area and the area is 60cm to m is 0.6m. Then the area is 0.6m×5m=3m^2. which gives a pressure of 15N/3m^2=5Pa

8 0
3 years ago
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