Question

What is the slope of the line that passes through the given points?

Answer 1

Answer:

B. 0

A. -¼

Step-by-step explanation:

-y₁ + y₂\-x₁ + x₂ = m

$\frac{-1 + 1}{-6 + 3} = \frac{0}{-3} = 0 \\ \\ \frac{-12 + 11}{-2 + 6} = - \frac{1}{4}$

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Answer 2

Answer:

For points :  (2, 12) and (6, 11)

, option A. is correct.

For points : (6, –1) and (–3, –1), option B. is correct

Step-by-step explanation:

We are given points in both the questions and we need to find the slope.

Slope refers to steepness of curve .It is basically change in y with change in x.

For two points $P\left ( x_1,y_1 \right )\,,\,Q\left ( x_2,y_2 \right )$, slope of line PQ is $\frac{y_2-y_1}{x_2-x_1}$

For points : (2, 12) and (6, 11)

Let $P\left ( x_1,y_1 \right )=(2, 12)\,,\,Q\left ( x_2,y_2 \right )=(6, 11)$,

Slope is $\frac{11-12}{6-2}=\frac{-1}{4}$ i.e, - 1 over 4

So, option A. is correct.

For points : (6, –1) and (–3, –1)

Let $P\left ( x_1,y_1 \right )=(6, -1)\,,\,Q\left ( x_2,y_2 \right )=(-3, -1)$

Slope is $\frac{-1+1}{-3-6}=\frac{0}{-9}=0$

So, option B. is correct