Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
0.164 = 16.4% probability that at least one color will be missing from the 10 selected balls.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Determine the probability that at least one color will be missing from the 10 selected balls.
Red missing:
Each time, there are 55 + 25 = 80 non-red balls, out of 100. So, in each of the 10 trials, 80% = 0.8 probability of not picking a red ball. The probability that no red ball is picked is given by:
(0.8)^10 = 0.1074
White missing:
55 + 20 = 75 non-white balls, out of 100, in each trial. The probability that no white ball is picked is given by:
(0.75)^10 = 0.0563
Blue missing:
45 non-blue balls, out of 100. The probability that no blue ball is picked is given by:
(0.45)^10 = 0.0003
Total:
0.1074 + 0.0563 + 0.0003 = 0.164
0.164 = 16.4% probability that at least one color will be missing from the 10 selected balls.
Answer:
8 pt
Step-by-step explanation: