Answer:
The inverse f-1(x) = ( x - 2) / 2.
Step-by-step explanation:
Let 2x + 1 = y
Now find x in terms of y:
2x = y - 1
x = (y - 1) / 2
Replace the x by the inverse f-1(x) and the y by x, so we have:
f-1(x) = ( x - 2) / 2.
Answer:
Absolute minimum = 1.414
Absolute maximum = 2.828
Step-by-step explanation:

For absolute minimum we take the minimum values of
and
.

Plugging in the minimum values in the function.

Absolute minimum value will be always positive.
∴ Absolute minimum = 1.414
For absolute maximum we take the maximum values of
and
.

Plugging in the maximum values in the function.

Absolute maximum value will be always positive.
∴ Absolute maximum = 2.828
1.) add 9 and 5 which is 14-6x