The rectangle shown has a perimeter of 106 cm and the given area. It’s length is 8 more than four times the width. Write and sol
ve a system of equations to find the dimensions of the rectangle
1 answer:
Answer:
Step-by-step explanation:
p = 106
L = 8 + 4W
p = 2L + 2W
p = 2(8 + 4W) + 2W
p = 16 + 8W + 2 W
p = 16 + 10W
106 = 16 + 10W
106 - 16 = 10W
90 = 10W
90/10 = W
9 = W
<h2>W = 9</h2><h2 />
L = 8 + 4W
L = 8 + 4(9)
L = 8 + 36
<h2>L = 44</h2>
44 + 44 + 9 + 9 = 106
44 * 9 = Area = 396
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