A black cat ______ all colors of light. A. Emits B. Reflects C. Refracts D. Absorbs
2 answers:
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Answer:
The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Explanation:
Given;
mass of bullet, m₁ = 4.2 g = 0.0042 kg
mass of hunter + gun = 72.5 kg
velocity of the bullet, u = 965 m/s
Momentum of the bullet when it was fired;
P = mv
P = 0.0042 x 965
P = 4.053 kg.m/s
Determine the recoil velocity of the hunter.
Total momentum = sum of the individual momenta
Total momentum = momentum of the bullet + momentum of the hunter
Apply the principle of conservation of momentum, sum of the momentum is equal to zero.
Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Answer:
a) is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.
b) is speed of the rocket going when it stops accelerating.
c)
d)
e) Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.
Explanation:
Given:
acceleration of rocket,
time for which the rocket accelerates,
<u>For the course of upward acceleration:</u>
using eq. of motion,
where:
initial velocity of the rocket at the launch
height the rocket travels just before its fuel finishes off
so,
a) is the height where the rocket stops accelerating and its fuel is finished and starts decelerating while it still continues to move in the upward direction.
<u>Now the velocity of the rocket just after the fuel is finished:</u>
b) is speed of the rocket going when it stops accelerating.
After the fuel is finished the rocket starts to decelerates. So, we find the height of the rocket before it begins to fall back towards the earth.
Now the additional height the rocket ascends before it begins to fall back on the earth after the fuel is consumed completely, at this point its instantaneous velocity is zero:
using equation of motion,
where:
acceleration due to gravity
final velocity of the rocket at the top height
c) So the total height at which the rocket gets:
d)
Time taken by the rocket to reach the top height after the fuel is over:
Now the time taken to fall from the total height:
Hence the total time taken by the rocket to strike back on the earth:
e)
Zero, since the average velocity is the net displacement per unit time and when the rocket strikes back the earth surface the net displacement is zero.