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Andrew [12]
4 years ago
15

What is the difference between the control group and the experimental group in an experimental study?​

Physics
2 answers:
nikitadnepr [17]4 years ago
8 0

Answer:

Explanation:

The only difference between the control and experimental group is the independent variable.

Talja [164]4 years ago
7 0
The controller doesn’t change and experimental does
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Achargingbullelephantwithamassof5240kgcomesdi- rectly toward you with a speed of 4.55 m/s. You toss a 0.150-kg rubber ball at th
Ierofanga [76]

Answer:

Given:

Mass of elephant = 5240 kg

The initial speed of the elephant = 4.55 m/s

Mass of the rubber ball, m, = 0.15 kg

Inital speed of the rubber ball, v = 7.81 m/s

On substitution  in V_{2f} = [\frac{2m_{1} }{m_{1} +m_{2} } ]V_{1f} + [\frac{m_{2}-m_{1}}{m_{1}+m_{2}  } ] v_{2f}

V_{2f} = [\frac{2*5240_{} }{5240_{} +0.15_{} } ](-4.55_{}) + [\frac{0.15_{}-5240_{}}{5240_{}+0.15_{}  } ] (7.81_{})

a) The negatıve sign shows that the ball bounces back in the direction opposite  to the incident

b)  it is clear that the velocity of the ball increases and therefore it is kinetic energy . The ball gains kinetic energy from the elephant.

8 0
3 years ago
A laser beam from Earth is reflected by a mirror placed on the Moon. If the speed of the beam is 3.00 x 108 m / s and the distan
Olin [163]

Answer:

1.27seconds

Explanation:

Speed = 324 m/s , Distance = 411.48m

Time = Distance/Speed

Time = 411.48/324 seconds

Time = 1.27seconds ( Ans)

3 0
3 years ago
Liang is warming a pot of soup on the stove.How is the motion of the particles in the soup different after the temperature of th
julsineya [31]
The particles will move faster due to the increased energy from the heat.
4 0
3 years ago
At the Sun Dagger in New Mexico, a dagger-shaped beam of sunlight pierces a spiral
nadya68 [22]

Answer:

D

Explanation:

At noon on the summer solstice. The sun dagger was used to observe astrological readings in the ancient time

7 0
3 years ago
An asteroid, whose mass is 3.6 × 10-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is
frosja888 [35]

Answer:

a) 2.02 years

b) 8.1 x 10⁻⁸.

Explanation:

Time period of a rotating body T² is proportional to radius of orbit R³ So

T₁² / T₂² = R₁³ /R₂³ ( T₁ and R₁ is time period and radius of orbit of the earth .)

1² / T₂² =( 1/1.6)³

T₂ = 2.02 years.

Kinetic energy of an orbiting body = 1/2 m v₀² ( v₀ is orbital speed)

= 1/2 m x 2 g R = m x G m/R² X R= m² x G /R

Kinetic energy of asteroid K₁ / kinetic energy of earth K₂ =

(mass of asteroid/mass of earth)² x( radius of earth / radius of asteroid)

=( 3.6 x 10⁻⁴)² x 1/1.6 = 8.1 x 10⁻⁸ .

7 0
3 years ago
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