Answer:
Given:
Mass of elephant = 5240 kg
The initial speed of the elephant = 4.55 m/s
Mass of the rubber ball, m, = 0.15 kg
Inital speed of the rubber ball, v = 7.81 m/s
On substitution in
=
+ ![[\frac{m_{2}-m_{1}}{m_{1}+m_{2} } ] v_{2f}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bm_%7B2%7D-m_%7B1%7D%7D%7Bm_%7B1%7D%2Bm_%7B2%7D%20%20%7D%20%5D%20v_%7B2f%7D)
=
+ ![[\frac{0.15_{}-5240_{}}{5240_{}+0.15_{} } ] (7.81_{})](https://tex.z-dn.net/?f=%5B%5Cfrac%7B0.15_%7B%7D-5240_%7B%7D%7D%7B5240_%7B%7D%2B0.15_%7B%7D%20%20%7D%20%5D%20%287.81_%7B%7D%29)
a) The negatıve sign shows that the ball bounces back in the direction opposite to the incident
b) it is clear that the velocity of the ball increases and therefore it is kinetic energy
. The ball gains kinetic energy from the elephant.
Answer:
1.27seconds
Explanation:
Speed = 324 m/s , Distance = 411.48m
Time = Distance/Speed
Time = 411.48/324 seconds
Time = 1.27seconds ( Ans)
The particles will move faster due to the increased energy from the heat.
Answer:
D
Explanation:
At noon on the summer solstice. The sun dagger was used to observe astrological readings in the ancient time
Answer:
a) 2.02 years
b) 8.1 x 10⁻⁸.
Explanation:
Time period of a rotating body T² is proportional to radius of orbit R³ So
T₁² / T₂² = R₁³ /R₂³ ( T₁ and R₁ is time period and radius of orbit of the earth .)
1² / T₂² =( 1/1.6)³
T₂ = 2.02 years.
Kinetic energy of an orbiting body = 1/2 m v₀² ( v₀ is orbital speed)
= 1/2 m x 2 g R = m x G m/R² X R= m² x G /R
Kinetic energy of asteroid K₁ / kinetic energy of earth K₂ =
(mass of asteroid/mass of earth)² x( radius of earth / radius of asteroid)
=( 3.6 x 10⁻⁴)² x 1/1.6 = 8.1 x 10⁻⁸ .