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Andrew [12]
4 years ago
15

What is the difference between the control group and the experimental group in an experimental study?​

Physics
2 answers:
nikitadnepr [17]4 years ago
8 0

Answer:

Explanation:

The only difference between the control and experimental group is the independent variable.

Talja [164]4 years ago
7 0
The controller doesn’t change and experimental does
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HELP PLEASE NOWWWW !!!! ( 1 )   Jill and Scott both road their bikes for 30 minutes.  Jill traveled 5 kilometers and Scott trave
katovenus [111]

#1

Jill and Scott both moves for 30 minutes

now if Jill cover 5 km distance and Scott cover 10 km distance

now we know that the formula of speed is given as

speed = \frac{distance}{time}

now we will have

speed of Jill

v = \frac{5}{0.5} = 10 km/h

speed of Scott

v = \frac{10}{0.5} = 20 km/h

so correct answer here is

<em>Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.</em>

<em>#2</em>

distance travelled by each car is given as

d = 400 miles

now here it is given that

time taken by green car

t_1 = 10 hours

time taken by yellow car

t_2 = 8 hours

now we can find the speed of two cars

speed = \frac{distance}{time}

speed of green car

v = \frac{400}{10} = 40 mph

speed of yellow car

v = \frac{400}{8} = 50 mph

so correct answer will be

<em>The yellow car was faster.  Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.</em>

6 0
3 years ago
Read 2 more answers
How many millimeters are there in one centimeter
Anika [276]
The answer is 10 millimeters in one <span>centimeter</span>
7 0
3 years ago
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A 5 cm radius isolated conducting sphere is charged so its potential is 100 V, relative to the potential far away. The charge de
MArishka [77]

The electric potential (V) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation:

V = \frac{kQ}{r}

Here,

k = Coulomb's constant

Q = Charge

r = Distance

If we rearrange the equation to find the distance we have,

Q=\frac{Vr}{k}

Q = \frac{(100)(5*10^{-2})}{9*10^9}

Q = 5.55*10^{-10} C

Now the value of the charge density is equivalent to the charge on the surface area of the sphere this is

\gamma = \frac{Q}{A_s}

\gamma = \frac{Q}{4\pi r^2}

\gamma = \frac{ 5.55*10^{-10}}{4\pi (5*10^{-2})^2}

\gamma = 1.76*10^{-8} C/m^2

4 0
3 years ago
How can i pass physics exam in 3 days?​
alexira [117]

Explanation:

you can pass the exam in 3 days by doing labouring hard, by understanding and by thinking theoretical and practising practically.

5 0
3 years ago
How does the speed of the wave compare between 300 hz and 400 hz
scoray [572]

The ratio between initial and final speed is 3:4

Explanation:

The speed of a wave is given by the wave equation:

v=f\lambda

where

v is the speed

f is the frequency of the wave

\lambda is the wavelength

In this problem, we have a wave with wavelength \lambda and initial frequency

f_1 = 300 Hz

So its speed can be written as

v_1 = f_1 \lambda = 300 \lambda

Later, its frequency changes to

f_2 = 400 Hz

Assuming that its wavelength has not changed, this means that its new speed is

v_2 = f_2 \lambda = 400 \lambda

By calculating the ratio between the two,

\frac{v_1}{v_2}=\frac{3}{4}

So, the ratio between initial and final speed is 3:4.

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

6 0
4 years ago
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